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Effectus [21]
3 years ago
12

A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that

apply.If the container is heated, the gas particles will lose kinetic energy and temperature will increase.
Physics
1 answer:
motikmotik3 years ago
7 0

Answer:

B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.

C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.

E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.

#FreeMelvin

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How much force is required to raise a 0.2 kg mass?
Firlakuza [10]

Answer:

1.96 N

Explanation:

6 0
2 years ago
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What eccentricity value results in a circular orbit?
Oxana [17]

Answer:

Zero

Explanation:

Given the equation of an ellipse:

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

The eccentrity of an ellipse is given by:

e=\sqrt{1-\frac{b^2}{a^2}}

For a circle, we have

a=b

Therefore the eccentricity of a circle is

e=\sqrt{1-\frac{1^2}{1^2}}=0

7 0
3 years ago
A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignit
Klio2033 [76]

Answer:

Compression ratio = 24.42

Explanation:

From Thermodynamic,

Adiabatic Equation ⇒ TV^{γ-1} = Constant.

⇒T₁V₁^{γ-1}  = T₂V₂^{γ-1} ..................(1)

Where T₁= initial Temperature, V₁ = Initial Volume, T₂ = final Temperature, V₂ = Final Volume.

Given:  T₁= 18°C we convert to  Kelvin(K) by adding 273.

∴      T₁= 18°C + 273 = 291K

        T₂ = 733° C  also,we convert to  Kelvin(K) by adding 273

 ∴      T₂ = 733° C +273 =1046K

          γ = 7/5

 ∴ Rearranging equation(1), we have

    (T₁/T₂) = (V₂/V₁)^{γ-1}................(2)

also rearranging equation(2) we have

   (V₁/V₂)^{γ-1} = (T₂/T₁).

Where (V₁/V₂) = Compression ratio.

∴ (V₁/V₂)^{(7/5)-1} =( 1046/291)

simplifying the index in the equation

I.e (7/5)-1 = (7-5 )/5 = 2/5.

(V₁/V₂)^2/5 =(1046/291)^2/5

Multiplying the power on both side of the equation by 5/2.

∴(V₁/V₂)^(2/5)×(5/2) = (1046/291)^(5/2)

⇒ V₁/V₂= (1046/291)^2.5=( 3.59)^2.5

    V₁/V₂ = 24.42.

∴ Compression ratio = 24.42

7 0
3 years ago
A baseball is thrown at a 28° angle and an initial velocity of 70 m/s. Assume no air resistance. How far did the ball travel hor
Genrish500 [490]

Answer:

414.9 m

Explanation:

First, become familiar with the horizontal, and vertical vector components.

Vertical vector: Vy = V × sin (θ).

Horizontal vector: Vx = V × cos(θ).

Distance traveled = Velocity vector × time in the air.

Time in the air given Vy = 2 × Vy / g (in respect to the metric of the vector).

Range of the projectile = Vx² / g

Time in the air given Vx = (Vx + √(Vx)² + 2gh) / g.

Given a 28° angle with an initial velocity of 70m/s, we have enough information to calculate!

Vx = 70 m/s × cos(28°) ≈ 61.806 m/s

Vy = 70 m/s × sin(28°) ≈ 32.863 m/s

t = 2 × Vy / g

t = 2 × ≈32.863 / 9.8

t = ≈65.726 / 9.8

t ≈ 6.7 s

Distance traveled (horizontal) = Vx × t = 61.806 × 6.7 ≈ 414.9 m

6 0
3 years ago
The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?
dlinn [17]

Answer:

Force on the singly charged ion will be 12.6\times 10^{-13}N

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be E=8MN/C=8\times 10^6N/C

It is given that ion so charge on ion will be equal to e=1.6\times 10^{-19}C

We have to find the electric force on the ion

Electric force is equal to F=qE, here q is charge and E is electric field

So force on the charge will be equal to F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N

So force on the singly charged ion will be 12.6\times 10^{-13}N

7 0
3 years ago
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