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2 years ago

7

Use the Fundamental Counting Principle to solve.

1 answer:

Vedmedyk [2.9K]2 years ago

7 0

$number \: of \: performances = 9 \\ note = \\ one \: insists \: on \: being \: last \\ number \: of \: flexible \: performances = 9 - 1 = 8 \\ \\ c( \gamma ) = 8P8 \times 1 \\ c( \gamma ) = 8! \\ c( \gamma ) = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \\ c( \gamma ) = 40320 \: ways$

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Answer:

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Step-by-step explanation:

If you are looking for the speed, then speed = distance/time

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speed = 9/10 ÷ 5/3 miles/hour

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3 years ago

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

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Step-by-step explanation:

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Point (-2, -4)

Point (2, 6)

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