<u>solution</u>
W=f×d×cos theta
=25N×16m×cos 45°
=400Nm×cos 45°
=282.84J
W=f×d×cos theta
=25N×7m×cos 10°
=175Nm×cos10°
=172.34J
Total workdone=282.84J+172.34J=455.18J
I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"
Answer and Explanation:
There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week
To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.
49 weeks×5 shifts= 245 shifts per operator per year
365×3 shifts= 1095 shifts per year
1095/245=4.5 operators per shift
total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14
total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928
Let's separate this problem into several parts:
1. The product of x
AND
2. The sum of 6 and 8
TIMES
3. The square of x
So translating this word problem into numbers, we have:
x TIMES (6+8) TIMES x²
so that is:
x * 14 * x²
which is:
14x^(2+1) = 14x³
5x5x5=125
12x3=36
36x3=108
108+125=233
233in^3 is the answer
I would but my teacher has a ad blocker on and I cant access the attachment :P
