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Troyanec [42]
3 years ago
15

The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimension

s of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0
<span>A = LW = 44
and
L = 3 + 2W
now substitute this into the first equation...
(3+2W)W=44
3W+2W^2=44

Rearranging
2W^2 + 3W - 44 = 0
Factoring we get
(2W + 11)(W - 4) = 0
so that
W = 4 inches
L = 11 inches</span>
den301095 [7]3 years ago
3 0
Let width = x   then length  = 2x + 3

so area = 119 = x(2x + 3)

2x^2 + 3x - 119 = 0
(2x + 17)(x - 7)  
x = 7 , -8.5
so x = 7   ( -8.5 can be ignored)
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Pls help me solve this question, also include step by step calculation ya. Thks
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Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

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luda_lava [24]

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Step-by-step explanation:

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Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for every 3 d
Katyanochek1 [597]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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