The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimension

Question

4 years ago

15

The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimension

s of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

Mathematics

2 answers:

ivann1987 [24] · Answer 1 · 2022-01-03T10:09:04+03:00

ivann1987 [24]4 years ago

6 0

<span>A = LW = 44
and
L = 3 + 2W
now substitute this into the first equation...
(3+2W)W=44
3W+2W^2=44

Rearranging
2W^2 + 3W - 44 = 0
Factoring we get
(2W + 11)(W - 4) = 0
so that
W = 4 inches
L = 11 inches</span>

den301095 [7] · Answer 2 · 2022-01-03T12:10:36+03:00

den301095 [7]4 years ago

3 0

Let width = x then length = 2x + 3

so area = 119 = x(2x + 3)

2x^2 + 3x - 119 = 0
(2x + 17)(x - 7)
x = 7 , -8.5
so x = 7 ( -8.5 can be ignored)