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madreJ [45]
2 years ago
11

Ramiro was on a two day road trip.on the first day he drove at an average speed of 40 mph.on the second day he drove at an avera

ge of 60 mph.if he drove 2 hours longer and went 20 miles farther on his first day find the total distance ramiro traveled on his road trip.
Mathematics
1 answer:
ratelena [41]2 years ago
3 0

Considering the relationship between velocity, distance and time, it is found that the total distance traveled was of 380 miles.

<h3>What is the relationship between velocity, distance and time?</h3>

Velocity is <u>distance divided by time</u>, that is:

v = d/t.

For the first day, we have that:

v = 40, t = t + 2, d = d + 20, hence:

40 = (d + 20)/(t + 2)

For the second day, we have that:

v = 60

60 = d/t

d = 60t

Then, replacing in the first equation:

40 = (60t + 20)(t + 2)

60t + 20 = 40t + 80

20t = 60

t = 3.

Then the distances are given by:

  • First day: d = 60t + 20 = 60 x 3 + 20 = 200 miles.
  • Second day: d = 60t = 60 x 3 = 180 miles.
  • Total: 200 miles + 180 miles = 380 miles.

More can be learned about the relationship between velocity, distance and time at brainly.com/question/28143163

#SPJ1

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jeyben [28]

Answer:

The length of the legs is 8.64cm and 14.64cm respectively

Step-by-step explanation:

I've added an attachment to aid my explanation.

At different intervals, I'll be making reference to it.

Given

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From the attachment, we have:

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Since, M is the Midpoint

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Substitute 8.5 for y

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v + x = 23.5 --------- (1)

Also, from the attachment

v + w + z = 25

Substitute 8.5 for z

v + w + 8.5 = 25

v + w = 25 - 8.5

v + w = 17.5 ----------- (2)

Subtract (2) from (1)

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We have that:

AB^2 = AC^2 + BC^2

The above can be replaced with

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Substitute 6 + w for x

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289 = 36 + 12w + w^2 + w^2

289 - 36 = 12w + 2w^2

253 = 12w + 2w^2

Reorder

2w^2 + 12w - 253 = 0

Solve using quadratic equation:

w = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where

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b = 12

c = -253

w = \frac{-12 \± \sqrt{12^2 - 4 * 2 * -253}}{2 * 2}

w = \frac{-12 \± \sqrt{144 + 2024}}{4}

w = \frac{-12 \± \sqrt{2168}}{4}

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Split:

w = \frac{-12 + 46.56}{4} or w = \frac{-12 - 46.56}{4}

w = \frac{34.56}{4} or w = \frac{-58.56}{4}

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But length can't be negative

So:

w = 8.64

Recall that: x = 6 + w

x = 6 + 8.64

x = 14.64

<em>Hence, the length of the legs is 8.64cm and 14.64cm respectively</em>

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