Answer:
75/19 <-- exact form 3.94736842... <---decimal form 3 18/19 <--- mixed number form explanation: I used a site to solve it so i don't get it wrong, I am not entirely sure this is right either but I think so
Step-by-step explanation:
Given mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", then the expression mCDE = mCDF+mFDE is true.
To get x, we will substitute the given angles into the formula as shown;
(10x – 18) = (3x + 14)+ (5x - 2)
10x-18 = 3x+5x+14-2
10x-18 = 8x+12
10x-8x = 12+18
2x = 30
x = 30/2
x = 15
Find the measure of each angle
For mCDF:
mCDF = 3x + 14
mCDF = 3(15)+ 14
mCDF = 45+14
mCDF = 59°
For mFDE:
mFDE = (5x - 2)
mFDE = 5(15) - 2
mFDE = 75-2
mFDE = 73°
For mCDE:
mCDE = (10x – 18)
mCDE = 10(15) - 18
mCDE = 150-18
mCDE = 132°
The coordinates of the point that is one-half the distance between A(-1,-2) and B(6,12) is (2.5,5)
What is the midpoint?
The mid-point lies midway between the two ends. Its x value lies in the middle of the other two x values. Its y value lies in the middle of the other two y values.
Given, 
Let M is a midpoint of AB, then
The midpoint of point AB is M(2.5,5)
Therefore, the coordinates of the point which is one-half the distance between A(-1,-2) and B(6,12) is M(2.5,5).
To learn more about the midpoint
brainly.com/question/24676143
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Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
28
Step-by-step explanation:
Cross multiply
18k = 12 x 42
18 k = 504
k = 504/18
k = 28
