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galben [10]
3 years ago
5

4% of ___days is 56 days

Mathematics
2 answers:
kykrilka [37]3 years ago
7 0
If 0.04x = 56 days

0.01x = 14 days
x = 14*100 = 1400 days
borishaifa [10]3 years ago
5 0
For this question you can say: 
4/100 = 56/? so (56*100)/40 = 140 so the answer is 140 days :))
i hope this is helpful 
have a nice ay 
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Question 9: Please help, what would be the length of the image of the segment GH?
shepuryov [24]

Answer:

<u><em></em></u>

  • <u><em>The length of the image of the segment GH would be 5 units.</em></u>

Explanation:

You can use the <em>center of dilation</em> as your origin of coordintes.

Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).

A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:

  • H = (0,0) → H' = 5 × (0,0) = (0,0)
  • G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

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3 years ago
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If 1 ounce=28.35 grams, how many grams are in one pound?
Andre45 [30]
There is 453.592 grams in 1 pound
7 0
3 years ago
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Find the value of x in the following triangle​
ozzi

Answer:

x = 124°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

x = 180° - (32 + 24)° = 180° - 56° = 124°

4 0
3 years ago
Simplify (2z^5)(12z^3)/4z^4
Sphinxa [80]

Answer:

6z^{4}

Step-by-step explanation:

Given in the question an expression,

\frac{ (2z^5)(12z^3)}{4z^4}

Step 1

Apply exponential "product rule"

x^{m}x^{n}=x^{m+n}

\frac{ 12(2)z^5)(z^3)}{4z^4}

\frac{ (24)z^5)(z^3)}{4z^4}

\frac{ 24(z^{(5+3)})}{4z^4}

\frac{ 24(z^{8})}{4z^4}

Step 2

Apply exponential " divide rule"

\frac{x^{m}}{x^{n}}=x^{m-n}

\frac{24/4(z^{8})}{z^4}

\frac{6(z^{8})}{z^4}

\frac{6(z^{8-4})}{1}

6z^{4}

5 0
3 years ago
A seagull was flying about sea level looking to catch a fish below sea level. The elevation above sea level was 125 1/2 feet. He
frez [133]

Answer:

The seagull's position halfway is 85.5 feet.

Step-by-step explanation:

The seagull is at 125 1/2 feet above the sea level.

The fish is at 45 1/2 feet below the sea level.

The distance between the seagull and fish = seagull's distance above the sea level + fish's distance below the sea level

                                                  = 125 1/2 + 45 1/2

                                                  = \frac{251}{2} + \frac{91}{2}

                                                  = \frac{342}{2}

                                                  = 171

The distance between the seagull and fish is 171 feet.

Since the seagull stops halfway, then;

seagull's position = \frac{171}{2}

                             = 85.5

The seagull's position halfway is 85.5 feet.

8 0
3 years ago
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