All categories

2 years ago

Oltp systems are designed to handle ad hoc analysis and complex queries that deal with many data items.

Mathematics

1 answer:

harkovskaia [24]2 years ago

3 0

Answer:

b) It is false

You might be interested in

Pls answer the pic below

Mice21 [21]

Answer:

B. 6

Step-by-step explanation:

the median is the middle of the set of numbers so the median of crunchy pb is 51 and the median of creamy is 45 so the difference between them is 51-45= 6

5 0

3 years ago

PLEASE HELPO MEEEEEEE Choose ALL the real-world scenarios below that would represent the

Kamila [148]

Answer:

I just need points

Step-by-step explanation:

I just need points

4 0

3 years ago

Simplify the given expression below:

Zina [86]

The answer will be C. OR 3. 11−13i

4 0

4 years ago

Read 2 more answers

0540-0058= ??? In military time

Tatiana [17]

Answer:

0442 (4:42 normal time)

btw plz give brainliest

3 0

3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

4 years ago