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Roman55 [17]
3 years ago
7

Simplify the given expression below:

Mathematics
2 answers:
Zina [86]3 years ago
4 0
The answer will be C. OR 3. 11−<span>13<span>i</span></span>
WINSTONCH [101]3 years ago
4 0

Answer:

The correct option is 3.

Step-by-step explanation:

The given expression is

(7-3i)\cdot(2-i)

We need to find the simplified form of given expression.

Using distributive property, the given expression can be written as

7\cdot(2-i)-3i\cdot(2-i)

7(2)+7(-i)-3i(2)-3i(-i)

On further simplification we get

14-7i-6i+3i^2

14-13i+3(-1)               [\because i^2=-1]

14-13i-3

On combining like terms we get

(14-3)-13i

11-13i

The simplified form of given expression is 11-13i. Therefore the correct option is 3.

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Which equation is related to this equation? b + 17 = 52
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A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
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