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Lostsunrise [7]
1 year ago
12

A parabola opens up and passes through (-4, 2) and (6, -3). How do you know that (-4, 2) is not the vertex

Mathematics
1 answer:
Ainat [17]1 year ago
4 0

Answer:

Step-by-step explanation:

The minimum is at the vertex of this parabola because it opens up.

Now if (-4, 2) is the minimum then  all the y values on the parabola must be > 2,

But we are given that  y = -3 is on the graph ( the point (6,-3) - that is y < 2 here,

Therefore (-4, 2)  cannot be the vertex .

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Find z0.755.
babunello [35]

Answer:

Option A is correct.

0.7734.

Step-by-step explanation:

Definition:  z-score indicates that how many standard deviations an element is from the mean.

It can be calculated from the following formula.

z = \frac{X-\mu}{\sigma}

where;  

z is the z-score,    

X is the value of the element,

\mu is the mean, and σ is the standard deviation.

To interprets z- score:

  • if a z-score < 0, it  represents an element less than the mean.
  • if a  z-score > 0, it represents an element greater than the mean.
  • if  z-score = 0, it  represents an element equal to the mean.

Given:  z < 0.755

then,

to find the value of z, look up the standardize normal distribution to the left of a z-score.

we get

z = 0.7734

6 0
3 years ago
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Company A: A 2-column table with 5 rows. The first column is labeled hours with entries 5, 12, 20, 29, 42. The second column is
ryzh [129]

Answer:

The correct answer is C.

Step-by-step explanation:

I took the test

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3 years ago
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Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation
Zolol [24]

Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form

The standard form of quadratic equation is

y= ax^2 + bx + c

When y=0 then the standard equation becomes

0= ax^2 + bx + c

Now we compare the given equation 0 = -x^2 + 4x - 7  with 0= ax^2 + bx + c and find the value of a, b,c

-x^2 can be written as -1x^2

0= ax^2 + bx + c

0 = -1x^2 + 4x - 7

a= -1 , b=4  and c=-7

The value of c is -7

4 0
3 years ago
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If segment LN is congruent to segment NP and ∠1 ≅ ∠2, prove that ∠NLO ≅ ∠NPM:
scoundrel [369]
The missing reason to complete Hector's proof is
<span>Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
</span>Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.
4 0
3 years ago
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The area of circle 1 is 6 square units. The area of circle 2 is 7 square units. Which of the following is true about the circumf
miskamm [114]

Answer:

C. The circumference of circle 1 is less than the circumference of circle 2.

Step-by-step explanation:

6<7

We know that the formula for the area of a circle is πr². This means the greater the radius, the greater the area.

We also know that the formula for circumference is 2πr. It is also dependent on radius. The greater the radius, the greater the circumference.

Given that Circle 2 has a greater area, this means that it has a greater radius which in turn means that it has a greater circumference.

C. The circumference of circle 1 is less than the circumference of circle 2.

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