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Lostsunrise [7]
1 year ago
12

A parabola opens up and passes through (-4, 2) and (6, -3). How do you know that (-4, 2) is not the vertex

Mathematics
1 answer:
Ainat [17]1 year ago
4 0

Answer:

Step-by-step explanation:

The minimum is at the vertex of this parabola because it opens up.

Now if (-4, 2) is the minimum then  all the y values on the parabola must be > 2,

But we are given that  y = -3 is on the graph ( the point (6,-3) - that is y < 2 here,

Therefore (-4, 2)  cannot be the vertex .

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I WILL GIVE BRAINLIEST TO CORRECT ANSWER
pickupchik [31]

Answer:

Hi there! The correct option is the third one, aka $176050.

Step-by-step explanation:

median is the value in middle

low from high:

168800

172200

174500

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183700

191400

174500 and 177600 is the middle.

174500 + 177600 = 352100

352100/2 = 176050

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3 years ago
The sides of a triangle measure 10 feet, 13 feet, and 17 feet.
yuradex [85]
A right triangles hypotenuse is the square root of both of the other side squared. The formula for this is a^2 + b^2= c^2, with c being the longest side. So 10 squared is 100, 13 squared is 169, but. 17 squared is 289. The sum of the other two sides are 269. So it doesn’t equal
3 0
1 year ago
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Express your answer as a monomial...<br>(6a^2b)(-7a^4b^7)
Arte-miy333 [17]
I hope this helps you


6. (-7).a^2+4.b^1+7

-42.a^6.b^8
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2 years ago
How do i solve this as an inequality?<br>a. 2x+6 &lt;14<br><br>please send a step by step!! :)​
Y_Kistochka [10]

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consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
tresset_1 [31]
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3  (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
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