Question

If f(x) = 3x2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?

Answer 1

Answer:

$(f-g)(2)=14$

Step-by-step explanation:

We are given the two functions:

$f(x)=3x^2+1\text{ and } g(x)=1-x$

And we want to find the value of:

$(f-g)(2)$

This is equivalent to:

$(f-g)(2)=f(2)-g(2)$

Substitute:

$=(3(2)^2+1)-(1-(2))$

Evaluate:

$=(3(4)+1)-(1-2)=(12+1)-(-1)=13+1=14$

Therefore:

$(f-g)(2)=14$