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3 years ago

7

Help??? Please math image

1 answer:

Olenka [21]3 years ago

4 0

Answer:

area: 24

lateral area: 36

total area: I am not sure.

volume: 24

Step-by-step explanation:

area: length times width

lateral area: (perimeter of base) times height

total area: I do not know, sorry.

volume: length times width times height.

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If one jar of peanut butter weights 1.6 pounds, how much does 5 jars of peanut butter weight?

Lady_Fox [76]

Answer:

5 × 1.6 = 8. The answer is 8 pounds.

Step-by-step explanation:

If you multiply 5 and 1.6, you get 8.

5 0

4 years ago

Read 2 more answers

two groups of friends are sharing apples of the same size. The first group of 3 friends share 4 apples. The second group of 4 fr

nikdorinn [45]

Answer:

The second group

Step-by-step explanation:

The first group is 4 apples for 3 friends.

= 4/3. They each got 1 & 1/3 of an apple.

The second group is 6 apples for 4 friends.

= 6/4. They each got 1 & 1/2 of an apple.

1 1/3 < 1 1/2, so friends in the second group get a larger portion of apples

3 0

3 years ago

If f(7)=22, then f-1(22)=

nignag [31]

Answer:

$f^{-1}$ (22) = 7

Step-by-step explanation:

The inverse function maps the output of the function back to its input

f(7) = 22 means when input is 7 the output is 22

The inverse maps the output 22 back to the input 7 , that is

$f^{-1}$ (22) = 7

4 0

3 years ago

HELPPPPPPPPPPPPPPPPPPP

spayn [35]

100 is da answer I think

8 0

3 years ago

Read 2 more answers

ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R

shutvik [7]

Answer:

$A'= (2,-1)$ and $R'=(4,-2)$ under this translation.

Step-by-step explanation:

A translation in $R^{2}$ is a mapping T from $R^{2}$ to $R^{2}$ defined by $T(x,y) = (x + v_1,y+v_2)$ , where $v=(v_1,v_2)$ is a fixed vector in $R^{2}$ .

From the problem we know that $T(2,4)=(3,2)$ , so we need to find the values $v_1$ and $v_2$ such that $T(2,4) = (2 + v_1,4+v_2)=(3,2)$ , so $3=2 + v_1$ and $4+v_2=2$ , thus $v_1=1$ and $v_2=2$ .

Then $T(x,y) = (x + 1,y-2)$ and

$T(1,1)=(1+1,1-2)=(2,-1)=A'$

$T(3,0)=(3+1,0-2)=(4,-2)=R'$

Therefore $A'= (2,-1)$ and $R'=(4,-2)$ . The triangles CAR and C'Q'R' are shown in the figure below.

7 0

3 years ago