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Zepler [3.9K]
2 years ago
5

The arrival times of geese to a gaggle were recorded (in seconds) and given in the stemplot below.

Mathematics
1 answer:
ki77a [65]2 years ago
5 0

The 12th fastest time a goose took to join the gaggle is 49 seconds.

<h3>What is the 12th fastest time a goose took to join the gaggle?</h3>

A Stem and Leaf Plot is a type of graph where the data is divided into a stem (the first digit or digits) and a leaf (usually the last digit).

The data in the stem plot arranged from the first fastest time it takes a goose to join the gaggle is: 13, 14, 15, 19, 19, 21, 27, 27, 28, 32, 45, 49, 49, 62, 62.

The 12th fastest time is 49

Please find attached the complete question. To learn more about stem plots, please check: brainly.com/question/12857419

#SPJ1

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What is the value of x in the equation -2/9x=2/5
densk [106]

Answer:

x = (-9)/5

Step-by-step explanation:

Solve for x:

(-2 x)/9 = 2/5

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (-2 x)/9 = 2/5 by -9/2:

(-9 (-2) x)/(2×9) = (-9)/2×2/5

Hint: | Express (-9)/2×(-2)/9 as a single fraction.

(-9)/2×(-2)/9 = (-9 (-2))/(2×9):

(-9 (-2))/(2×9) x = (-9)/2×2/5

Hint: | Express (-9)/2×2/5 as a single fraction.

(-9)/2×2/5 = (-9×2)/(2×5):

(-9 (-2) x)/(2×9) = (-9×2)/(2×5)

Hint: | In (-9 (-2) x)/(2×9), divide -9 in the numerator by 9 in the denominator.

(-9)/9 = (9 (-1))/9 = -1:

(-2-1 x)/2 = (-9×2)/(2×5)

Hint: | In (-(-2) x)/2, divide -2 in the numerator by 2 in the denominator.

(-2)/2 = (2 (-1))/2 = -1:

--1 x = (-9×2)/(2×5)

Hint: | Multiply all instances of -1 in -(-x).

(-1)^2 = 1:

x = (-9×2)/(2×5)

Hint: | Cancel common terms in the numerator and denominator of (-9×2)/(2×5).

(-9×2)/(2×5) = 2/2×(-9)/5 = (-9)/5:

Answer: x = (-9)/5

7 0
2 years ago
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2 years ago
random sample has been taken from a normal population and two confidence intervals constructed using exactly the same data. The
Zepler [3.9K]

The sample mean of the random sample is 50

The margin of error (E) is the amount of error allowed in the random sample.

The confidence interval (CI) is given by:

CI = μ ± E = (μ - E, μ + E)

Given a confidence interval of (38.02, 61.98), hence:

μ - E = 38.02     (1)

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Hence solving equations 1 and 2 simultaneously gives:

μ = 50, E = 11.98

Hence the sample mean of the random sample is 50

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