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Assoli18 [71]
3 years ago
13

0.65,0.59,3/5 least to greatest

Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0
1.)3/5
2.)0.59
3.)0.65
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As a​ follow-up to a report on gas​ consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f
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The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

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Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have T = 1.9855.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{5.6}{\sqrt{96}} = 0.57

Now, we multiply T and s

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For the lower end of the interval, we subtract the mean by M. So 19.6 - 1.31 = 18.29

For the upper end of the interval, we add the mean to M. So 19.6 + 1.31 = 20.91

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

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Step-by-step explanation:

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