Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
6^2
Step-by-step explanation:
it is a division between two power with the same base, so we have to subtract the exponents
6^(6-4) = 6^2
300 acres. because <span>multiply 60 by 5.</span>
Answer:
Step-by-step explanation:
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