1 year ago

Suppose f(x) and g(x) are differentiable functions satisfying f(1) = f′(1) = 2. Let

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1 answer:

just olya [345]1 year ago

3 0

Answer:

1777777777888876332222233

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Step-by-step explanation:

Distance between two points (x1,y1) and (x2,y2) on coordinate plane is given by

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Given points in the problem are (3,-5) and (3,-2).

Thus distance between points (3,-5) and (3,-2).

$distance = \sqrt{(x1-x2)^2 +(y1-y2)^2 }\\=>distance = \sqrt{(3-3)^2 +(-5-(-2))^2 }\\=>distance = \sqrt{(0)^2 +(-5+2)^2 }\\\\=>distance = \sqrt{0 +(-3)^2 }\\\\=>distance = \sqrt{9 }\\=>distance = 3$

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