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Vaselesa [24]
3 years ago
5

Heidi grew her hair out for many years. Her hair was 12/10 of a meter long. She donated her hair by cutting off 5/6 of a meter.

How long is Heidi's hair now?
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

0.37 meters.

Step-by-step explanation:

12/10 of 1 meter = 1.2meters

5/6 of 1 meter = 0.8333333333 meters.

1.2 meters - 0.833333333 meters = 0.366666667 meters.

~0.37 meters

Please give brainliest if I am correct, if I am not; sorry about that.

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Determine the domain and the range of the graph.
dimulka [17.4K]

Answer:

Domain: (-∞,∞)

Range: -1

Step-by-step explanation:

Domain means the x-coordinates covered:

(-∞,∞)

Range means the y-coordinates covered:

Only -1 because there are no other existing y-coordinates.

5 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
Only 18 people are allowed on a ride at the same time. There are 157 people waiting in line. How many groups of riders will ther
IrinaK [193]

Answer:

Step-by-step explanation:

Divide 157 by 8 to see how many groups there are.

157/18=8r13. So you can round up to 9 groups of riders as there is a max of 18 at a time.

7 0
3 years ago
Which shows the image of rectangle ABCD after the rotation (x, y)<br> (-y, x)?
AysviL [449]

Answer:

Rotation through -90

Step-by-step explanation:

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6 0
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Answer:

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