<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>
I’m 90% sure that the answer is 36x
Answer:
v=1460.26536188 units^3
Step-by-step explanation:
Volume for a cylinder is:
V=πr^2h
Substitute 6 in for r and 13 in for h
V=π(6^2)(13)
V=π(36)(13)
V=π468
v=1460.26536188 units^3
Hope this helps! :)
