which equation is represented by the graph below a. y=1/8ex b.y=1/2ex c.y=2ex. d.y=8ex

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0

3 years ago

EXERCISE

Olin [163]

Answer:

1)The probability that the ball drawn is not red is 6 /14

2)Probability of getting either a prime or a multiple of 3 is 7/10

3)Probability of drawing three balls without replacement such that all three are Same colour is 0.0747

Probability of drawing three balls without replacement such that all three are different colour is 0.5

Step-by-step explanation:

1) A ball is drawn randomly from a bag containing 8 red, 4 blue and 2 green identical balls. Find the probability that the ball drawn is not red.

No. of red balls = 8

No. of blue balls = 4

No. of green balls = 2

Total no. of balls = 8+4+2=14

P(Getting red bal)= $\frac{8}{14}$

P( ball drawn is not red) = $1 - \frac{8}{14}=\frac{6}{14}$

So,the probability that the ball drawn is not red is 6 /14

2)What is the probability that a number chosen at random from the integers between 1 and 10 inclusive is either a prime or a multiple of 3?

Numbers : 1 ,2,3,4,5,6,7,8,9,10

Prime numbers: 2,3,5,7 = 4

Multiple of 3 = 3,6,9 =3

So, Probability of getting prime number = $\frac{4}{10}$

Probability of getting multiple of 3 = $\frac{3}{10}$

So, Probability of getting either a prime or a multiple of 3= $\frac{4}{10}+\frac{3}{10}=\frac{7}{10}$

Hence Probability of getting either a prime or a multiple of 3 is 7/10

3)A bag contains four red balls, five blue balls and six green balls. Three balls are drawn from the bag at random without replacement. What is the probability that all three are:

The same colour

Different colour

No. of red balls = 4

No. of blue balls = 5

No. of green balls = 6

Total balls = 15

Case 1 :all three are Same colour

So, probability of drawing three balls without replacement such that all three are Same colour = $\frac{4}{15} \times \frac{3}{14} \times \frac{2}{13}+\frac{5}{15} \times \frac{4}{14} \times \frac{3}{13}+\frac{6}{15} \times \frac{5}{14} \times \frac{4}{13}=0.0747$

So, probability of drawing three balls without replacement such that all three are different colour = $\frac{4}{10} \times \frac{5}{9} \times \frac{6}{8}+\frac{5}{10} \times \frac{4}{9} \times \frac{6}{8}+\frac{6}{10} \times \frac{5}{9} \times \frac{4}{8}=0.5$

So,probability of drawing three balls without replacement such that all three are Same colour is 0.0747

So,probability of drawing three balls without replacement such that all three are different colour is 0.5

3 0

4 years ago

A square has a side lengths of 9, use the pythagorean theorem to find the length of the diagonal

Semmy [17]

diagonal = 9√2 ≈ 12.73

the diagonal splits the square into 2 right triangles with the hypotenuse being the diagonal of the square

using Pythagoras' identity

d = √(9² + 9²) = √162 = 9√2 ≈ 12.73 ( to 2 dec. places )

5 0

3 years ago

Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s

Harman [31]

Answer:

Option (c) is correct.

Step-by-step explanation:

Given equation is :

$s=\dfrac{a+b+c}{3}$

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

$3s=a+b+c$

Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

⇒ a=3s-b-c

The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

5 0

3 years ago

Read 2 more answers

Jenny has saved $600 from her summer job. During the school year, she withdraws $20 from her account every week for her daily ex

mel-nik [20]

Answer:

The answer is 14 weeks

6 0

3 years ago