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Jobisdone [24]
3 years ago
10

Jenny has saved $600 from her summer job. During the school year, she withdraws $20 from her account every week for her daily ex

penses. She wants to keep more than $300 in the account for college. The number of weeks, w, that Jenny can withdraw money from her account is represented by the inequality 600 − 20w > 300. How many weeks can Jenny continue to withdraw $20 from her account?
Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

The answer is 14 weeks


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15 books each of dimension 2 cm x 4 cm x 5 cm are stacked on a she
Elena L [17]

Answer:

30cm

Step-by-step explanation:

Assuming that the thickness of the books is 2cm (This is a reasonable assumption, as books are almost always longer and wider than they are thick, and assuming that the books are stacked flat on top of one another, faces up or down, and not sideways, the question becomes 'What is the height of 15 books stacked on top of one another, if each book is 2cm thick?' The answer to this question is 15*2 or 30.

7 0
3 years ago
Read 2 more answers
The median weight of 15 dogs in a pet store is 12 pounds. Which action could change the median?
never [62]

Answer:

If there was another dog whose weight was greater than or less than 12.

Step-by-step explanation:

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 4

When we add 4 to the data set we have:

184 ÷ 16 = 11.5

This changed the median.

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 28

When we add 28 to the data set we have:

208 ÷ 16 = 13

This also changed the median.

7 0
3 years ago
What is the value of k if (1, 1) is a solution of 2x + 7y=k?​
Mekhanik [1.2K]
Answer: k=9
reasoning: just plug in 1 for x and 1 for y
5 0
2 years ago
Help me math exam please​
Sedaia [141]
Here you go the answer is 110

6 0
3 years ago
In a certain chemical reaction, a substance is converted into another substance at a rate proportional to the square of the amou
morpeh [17]

Answer:

Q (t) =  \frac{90}{7t +2 }

Q(2) = 5.63 \ g

Step-by-step explanation:

Let Q(t) be the first substance at time t. We know that the rate of change is directly proportional to Q^2.

Hence we can write it as:

\frac{dQ}{dt} \propto Q^2\\\\\frac{dQ}{dt} = kQ^2

<u>Step 1: Integrating the function to form an equation:</u>

<u />\frac{dQ}{dt} = kQ^2\\\\\frac{dQ}{Q^2} = k \ dt\\\\\int  \frac{dQ}{Q^2} = \int k \ dt\\\\- \frac{1}{Q} = kt + C   ----------------------------------------------- equation (1)

<u>Step 2: Substitute the value Q(0) = 45 in equation 1 to find value of C.</u>

<u />-\frac{1}{Q} = kt + C\\\\-\frac{1}{45} = k(0) + C\\\\-\frac{1}{45} = C\\\\\\-\frac{1}{Q} = kt - \frac{1}{45}\\---------------------------------------------- equation (2)

<u>Step 3: Substitute the value Q(1) = 10 in equation 2 to find the value of k.</u>

<u />-\frac{1}{Q} = kt - \frac{1}{45}\\\\-\frac{1}{10} = k(1) - \frac{1}{45}\\\\-\frac{1}{10} - \frac{1}{45} = k \\\\\frac{2-9}{90} = k\\\\-\frac{7}{90} = k

<u>Step 4: Form the equation and simplify it.</u>

<u />-\frac{1}{Q} = -\frac{7}{90} t - \frac{1}{45}\\  \\\frac{1}{Q} = \frac{7}{90}t + \frac{2}{90}\\\\\frac{1}{Q} = \frac{7t + 2}{90}\\\\\\\bullet \ cross - multiply \ the \ equation \\\\Q = \frac{90}{7t + 2}<u />

<u />

<u>Step 5: To find the amount of substance after 2 hours, we substitute the value of t with 2.</u>

<u />Q = \frac{90}{7t + 2}\\\\Q = \frac{90}{7(2) + 2}\\\\Q = \frac{90}{14+ 2}\\\\Q = \frac{90}{16}\\\\Q = 5.625 \approx 5.63<u />

<u />

The amount of substance after 2 hours is 5.63 grams.

5 0
3 years ago
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