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Jobisdone [24]
3 years ago
10

Jenny has saved $600 from her summer job. During the school year, she withdraws $20 from her account every week for her daily ex

penses. She wants to keep more than $300 in the account for college. The number of weeks, w, that Jenny can withdraw money from her account is represented by the inequality 600 − 20w > 300. How many weeks can Jenny continue to withdraw $20 from her account?
Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

The answer is 14 weeks


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FREE POINTS!
k0ka [10]

Answer:

16

Step-by-step explanation:

12+4=16

3 0
3 years ago
Read 2 more answers
What is 2a・420 divided by 3z when z=34 and a=56
Maksim231197 [3]

461.176470588

Explanation:

2×56=112

112×420=47040

---------------------------------

3×34=102

---------------------------------

47040÷102=461.176470588

7 0
2 years ago
✨ B R A I N L I E S T
miv72 [106K]

1

:x

2

+y

2

−6x−9y+13=0

(x−3)

2

+(y−

2

9

)

2

−9−

4

81

+13=0

(x−3)

2

+(y−

2

9

)

2

=

4

65

Here,

r

1

=

2

65

C

1

=(3,

2

9

)

Equation of another circle-

S

2

:x

2

+y

2

−2x−16y=0

(x−1)

2

+(y−8)

2

−1−64=0

(x−1)

2

+(y−8)

2

=65

Here,

r

2

=

65

C

2

=(1,8)

Distance between the centre of two circles-

C

1

C

2

=

(3−1)

2

+(8−

2

9

)

2

C

1

C

2

=

4+

4

49

=

2

65

∣r

2

−r

1

∣=

∣

∣

∣

∣

∣

∣

65

−

2

65

∣

∣

∣

∣

∣

∣

=

2

65

∵C

1

C

2

=∣r

1

−r

2

∣

Thus the two circles touches each other internally.

Since the circle touches each other internally. The point of contact P divides C

1

C

2

externally in the ratio r

1

:r

2

, i.e.,

2

65

:

65

=1:2

Therefore, coordinates of P are-

⎝

⎜

⎜

⎜

⎜

⎜

⎛

1−2

1(1)−2(3)

,

1−2

1(8)−2(

2

9

)

⎠

⎟

⎟

⎟

⎟

⎟

⎞

=(5,1)

Therefore,

Equation of common tangent is-

S

1

−S

2

=0

(5x+y−6(

2

x+5

)−9(

2

y+1

)+13)−(5x+y−2(

2

x+5

)−16(

2

y+1

))=0

2

−6x−9y−13

+x+8y+13=0

4x−7y−13=0

Hence the point of contact is (5,1) and the equation of common tangent is 4x−7y−13=0.

4 0
3 years ago
Read 2 more answers
Two ships leave a harbor at the same time. One ship travels on a bearing Upper S 14 degrees Upper W at 15 miles per hour. The ot
jekas [21]

Answer:

69.94 miles

Step-by-step explanation:

The distance d₁ the first ship moves after 3 hours is 3 hours × 15 miles per hours = 45 miles

The distance d₂ the second ship moves after 3 hours is 3 hours × 12 miles per hours = 36 miles.

The angle the first ship's direction makes in the North-East direction is 90° - 75° = 15°

The angle the second ship's direction makes in the South-West direction  = 14°

The distance moved by the two ships form the side of a triangle. The angle,  θ between the two ship directions is 14° + 90° + 15° = 119°

Using the cosine rule, we find the distance d between the two ships

d = √(d₁² + d₂² -2d₁d₂cosθ)

= √(45² + 36² -2×45×36cos119°)

= √(2025 + 1296- (-1570.78))

= √(3321 + 1570.78)

= √4891.78

= 69.94 miles

4 0
3 years ago
The first photo in the collage is what I should make a copy of, anyone has any knowledge on how to add the numbers apart of the
raketka [301]

Answer:

uh no new copy

Step-by-steYou can make a new table to add the amounts and copy the pre-existing amounts or just add a new bar, but I guess it will be better if you just do it again.

3 0
3 years ago
Read 2 more answers
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