Question

(Refer to the attached image)​

Answer 1

Answer:

D.  10

Step-by-step explanation:

To find the distance between two points, use the distance formula:

Distance between two points

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}$

Define the two points:

$\textsf{Let }(x_1,y_1)=(4,-3)$

$\textsf{Let }(x_2,y_2)=(-4,3)$

Substitute the two defined points into the distance formula and solve for d:

$\implies d=\sqrt{(-4-4)^2+(3-(-3))^2}$

$\implies d=\sqrt{(-4-4)^2+(3+3)^2}$

$\implies d=\sqrt{(-8)^2+6^2}$

$\implies d=\sqrt{64+36}$

$\implies d=\sqrt{100}$

$\implies d=\sqrt{10^2}$

$\implies d=10$

Therefore, the distance between the two given points is 10 units.

Answer 2

Formula given by

$\boxed{\sf Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

$\\ \tt{:}\longrightarrow D=\sqrt{(-4-4)^2+(3+3)^2}$

$\\ \tt{:}\longrightarrow D=\sqrt{8^2+6^2}$

$\\ \tt{:}\longrightarrow D=\sqrt{10^2}$

$\\ \tt{:}\longrightarrow D=10units$

Option D