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1 year ago

Find the area of the triangle A 47° b 32 ft C 19 ft

Mathematics

2 answers:

Solnce55 [7]1 year ago

4 0

Answer:

222 [ft²].

Step-by-step explanation:

1. the required area can be calculated according to the formula:

A=0.5*b*c*sin(A);

2. after substitution of b=32; c=19 and sin(A)≈0.7313537:

A=0.5*32*19*0.7313537=222.3315248 [ft²].

NemiM [27]1 year ago

4 0

The answer is A ……………

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Last year at a certain high school, there were 125 boys on the honor roll and 80 girls on the honor roll. This year, the number

Elodia [21]

Answer:

6.8% decrease

Step-by-step explanation:

a drop of 8% means that only 92% of 125 boys remained on honor roll from last year; .92 x 125 = 115

a drop of 5% means that only 95% of 80 girls remained on honor roll from last year; .95 x 80 = 76

total number of students on honor roll last year = 125 + 80 = 205

total number of students on honor roll this year = 115 + 76 = 191

percent of change = (191 - 205) ÷ 205 = -14/205 = -.068

-.068, which represents a 6.8% decrease

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2 years ago

Malik drinks 48 ounces of water each day. How many ounces of water will he drink in 16 days? 64 192 336 768

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1 year ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

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alukav5142 [94]

False.
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3 years ago

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