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2 years ago

8

Graph the line y= -3x - 2

1 answer:

sashaice [31]2 years ago

6 0

Answer:

The graph is attached below.

Step-by-step explanation:

Given the line equation

$y=\:-3x\:-\:2$

Comparing the line equation with the slope-intercept form

$y=mx+b$

where m is the slope, and b is the y-intercept

Here:

m = -3

b = -2

When

x = 0, then y = -2 ∵ y = -3x - 2 = -3(0) - 2 = -2

When

x = 1, then y = -5 ∵ y = -3x - 2 = -3(1) - 2 = -3 - 2 = -5

The graph is attached below.

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2 years ago

Solve using quadratic formula for 2x^(2)-10x+5=0

sergij07 [2.7K]

Answer:

$x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}$

Step-by-step explanation:

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

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$=\sqrt{10^2-4\cdot \:2\cdot \:5}$

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$=\sqrt{10^2-40}$

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$=\sqrt{100-40}$

$\mathrm{Subtract\:the\:numbers:}\:100-40=60$

$=\sqrt{60}$

$60\:\mathrm{divides\:by}\:2\quad \:60=30\cdot \:2$

$=2\cdot \:30$

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$=2\cdot \:2\cdot \:15$

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Apply Radical Rule:

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Apply Radical Rule:

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$\mathrm{Refine}$

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$\mathrm{Cancel\:the\:common\:factor:}\:2$

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$\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}$

$=\frac{10-2\sqrt{15}}{2\cdot \:2}$

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$=\frac{10-2\sqrt{15}}{4}$

$=\frac{2\left(5-\sqrt{15}\right)}{4}$

$\mathrm{Cancel\:the\:common\:factor:}\:2$

$=\frac{5-\sqrt{15}}{2}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}$

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