In anticipation of receiving a fertilized ovum, the lining of the uterine wall

1 answer:

7 0

Every month, the lining of the uterus becomes thicker in preparation for an egg that has been fertilized to place itself there. In the event that this transpires, hormones originating from the reproductive organs will stabilize the vascular tissue of the endometrium, which in turn will offer a setting for the embryo to grow in.

This is further explained below.

<h3>What is the uterine wall?</h3>

Generally, The uterine lining grows every month in anticipation of the implantation of a fertilized ovum. When this happens, the endometrium's vascular tissue is stabilized by hormones from the reproductive organs, providing an environment for the growing fetus.

In conclusion, There are three distinct layers of muscle tissue that compose the uterine wall. The muscle fibers are intertwined with the connective tissue of blood vessels, elastic fibers, and collagen fibers, and they may run in either of three directions: longitudinally, circularly, and obliquely. As the baby grows within the uterus, this thick muscular wall begins to stretch out and eventually becomes much thinner.

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37 cos(x2) dx 0 Do the following. (a) Find the approximations T8 and M8 for the given integral. (Round your answer to six decima

dusya [7]

The approximations T8 and M8 for the given integral are:

T8 = 33.386321; and
M8 = 33.50794

<h3>What is an integral?</h3>

An Integral is a variable of which a given function is the derivative, i.e. it gives that function when differentiated and may express the area under the curve of the function's graph.

<h3>What is the explanation to above answer?</h3>

Given:

F(x) = 37 cox (x²)

Internal = [0,1] n = 8 in Δ x = 1/8

The sub intervals are:

[0, 1/8], [1/8, 2/8], [2/8, 3/8], [ 3/8, 4/8], [ 4/8, 5/8], [ 5/8, 6/8], [6/8, 7/8], [ 7/8, 1]

The mid points are given as:

1/16, 3/16, 5/16, 7/16, 9/16, 11/16, 13/16, 15/16

and X₀ = 0, X₁ = 1/8, X₂ = 2/8

Using the Trapezium Rule which states that:

$\int\limits^1_0 cos(x)^{2} } \, dx$ = Δx/2 $[f(xo) + 2f(x1) 2f(x2) + ....+ 2f(x7) + f(x8)]$