<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,
![f(x)=x^3-x^2+6x-6](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3-x%5E2%2B6x-6)
The zeros of the polynomials are,
![\Rightarrow f(x)=0](https://tex.z-dn.net/?f=%5CRightarrow%20f%28x%29%3D0)
![\Rightarrow x^3-x^2+6x-6=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E3-x%5E2%2B6x-6%3D0)
![\Rightarrow x^2(x-1)+6(x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%28x-1%29%2B6%28x-1%29%3D0)
![\Rightarrow (x^2+6)(x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x%5E2%2B6%29%28x-1%29%3D0)
![\Rightarrow (x^2+6)=0,(x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x%5E2%2B6%29%3D0%2C%28x-1%29%3D0)
![\Rightarrow x=\sqrt{-6},\ x=1](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D%5Csqrt%7B-6%7D%2C%5C%20x%3D1)
![\Rightarrow x=1,\ \pm \sqrt6i](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D1%2C%5C%20%5Cpm%20%5Csqrt6i)
Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
<span>Just find the volume of each cube separately and add together the results. First cube has side length 5h^2. What is the formula for the volume of a cube? Second cube has side length 3k. Whats its volume?</span>
Kevin will have enough. He will need to pay $23.10.
5% of $22 is $1.10.
22+1.10=23.10
23.10 is less than 24
Answer: hi im mongraal
Step-by-step explanation:
In mathematics, a cube root of a number x is a number y such that y³ = x. All nonzero real numbers, have exactly one real cube root and a pair of complex conjugate cube roots, and all nonzero complex numbers have three distinct complex cube roots. For example, the real cube root of 8, denoted ³√8, is 2, because 2³ = 8, while the other cube roots of 8 are −1 + √3i and −1 − √3i. The three cube roots of −27i are 3i, 3√(3)/2-3/2i, and -3√(3)/2-3/2i.
Combine like terms
-2x-4=-2x-4
Since the equations are the same, the answer is infinitely many solutions.