A - 3b = 4 . . . . (1)
a = b - 2 . . . . . (2)
Putting (2) into (1), we have
b - 2 - 3b = 4
-2b = 4 + 2 = 6
b = 6/-2 = -3
From (1), a = b - 2 = -3 - 2 = -5
Hence, solution = (-5, -3)
Answer:
(−2,10)
Step-by-step explanation:
hope this helps
P = 300 $; r = 0.06; t = 20; n = 1
A = P ( 1 + r/n)^n*t
= 300 ( 1 + 0.06) ²⁰
= 300 ( 1.06) ²⁰
= 962.14
Answer:
slope = -3
Step-by-step explanation:
1) Rearrange eqn into slope intercept form
slope intercept form: y = mx + b
where...
m = the slope
b = the y-intercept (where the line crosses the y axis)
3x + y = 12
y = -3x+12
2) Know parallel rule. A line that runs parallel has the same slope but a different y-intercept
So the slope is: -3
we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
