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Shkiper50 [21]
3 years ago
14

ABCD is a isosceles trapezoid with AB=10, DB=8 and angle A=120 degrees what is the length of CD

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

The answer is 10.6 (I'm sorry if it's wrong)

Step-by-step explanation:

found out what D and B is (they both are 4 I think) then add 10 with 8 then divide 120 with 18 which is 6.6 then add what D is and then I got 10.6

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Answer:

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Step-by-step explanation:

∫x2/x1−20x2−125dx

Should be

∫x²/(x²−20x−125)dx

First of all let's factorize the denominator.

x²−20x−125= x²+5x-25x-125

x²−20x−125= x(x+5) -25(x+5)

x²−20x−125= (x-25)(x+5)

∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx

x²/(x²−20x−125) =x²/((x-25)(x+5))

x²/((x-25)(x+5))= a/(x-25) +b/(x+5)

x²/= a(x+5) + b(x-25)

Let x=25

625 = a30

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a= 125/6

Let x= -5

25 = -30b

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b= -5/6

x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)

∫x²/(x²−20x−125)dx

=∫125/6(x-25) -∫5/6(x+5) Dx

= 125/6(In(x-25)) - 5/6(In(x+5))+C

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