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Shkiper50 [21]
3 years ago
14

ABCD is a isosceles trapezoid with AB=10, DB=8 and angle A=120 degrees what is the length of CD

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

The answer is 10.6 (I'm sorry if it's wrong)

Step-by-step explanation:

found out what D and B is (they both are 4 I think) then add 10 with 8 then divide 120 with 18 which is 6.6 then add what D is and then I got 10.6

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Lady_Fox [76]
Let's solve your system by substitution.
y
=
−
2
x
+
7
;
y
=
5
x
−
7

Step: Solve
y
=
−
2
x
+
7
for y:
y
=
−
2
x
+
7

Step: Substitute
−
2
x
+
7
for
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in
y
=
5
x
−
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:
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=
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x
−
7
−
2
x
+
7
=
5
x
−
7
−
2
x
+
7
+
−
5
x
=
5
x
−
7
+
−
5
x
(Add -5x to both sides)
−
7
x
+
7
=
−
7
−
7
x
+
7
+
−
7
=
−
7
+
−
7
(Add -7 to both sides)
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7
x
=
−
14
−
7
x
−
7
=
−
14
−
7
(Divide both sides by -7)
x
=
2

Step: Substitute
2
for
x
in
y
=
−
2
x
+
7
:
y
=
−
2
x
+
7
y
=
(
−
2
)
(
2
)
+
7
y
=
3
(Simplify both sides of the equation)

Answer: x=2 and y=3
6 0
3 years ago
The rectangular prism is to be sliced perpendicular to the shaded face and is to pass through point B, parallel to the front fac
Natasha_Volkova [10]

Answer:

the answer is c i took the quiz

Step-by-step explanation:

5 0
3 years ago
Which is equivalent to V4500° after it has been simplified completely?
Rufina [12.5K]

Answer:

Step-by-step explanation:

5 0
3 years ago
F(x) = x2 + 1<br> What is f(f(x))?
nadya68 [22]

Answer:The x could just mean a variable but I don't know what F means sorry.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
You flip a coin and then roll a 6-sided number cube (a die).
expeople1 [14]

Answer:

a)  No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.

b) Yes.

  • Let event 1 be flipping a coin and event 2 be rolling a die.
  • Let event 1 be rolling a die and event 2 be flipping a coin.

The likelihood that any outcome will occur will not change, as the events are independent.

c) see attached

d)   12 outcomes  (H = head, T = tail, numbers represent the value of the die)

H 1           T 1

H 2          T 2

H 3          T 3

H 4          T 4

H 5          T 5

H 6          T 6

e)  

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf P(even)=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}

\implies \sf P(head)=\dfrac{1}{2}

\implies \sf P(even)\:and\:P(head)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}

6 0
2 years ago
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