A professional basketball team won 48 games and lost 32. what fraction of the games did the team win?

Mathematics

2 answers:

navik [9.2K]2 years ago

5 0

Answer:3/5 of the games

Step-by-step explanation: The total number of games played by the team is 48+32 = 80 games. out of hose 80, they won 48 so they won 48/80 games. We can simplify this by dividing both sides by 8 to get 6/10. Which is 60%. Finally we can simplify again by dividing the fraction by 2/2 to get 3/5.

katrin [286]2 years ago

4 0

Answer:

48/80 = 6/10

Step-by-step explanation:

48 wins

+ 32 lost

= 80 total games

Then the fraction of the games win is:

48/80

= 6/10

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Answer the following: a) 2x32 =<br> b) (2 x 3)2 =

wel

Answer:

a) 64 b) 12

Step-by-step explanation:

32 + 32 = 64

2*3 = 6

6*2 = 12

6 0

3 years ago

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Azmyne decided to spend 6 1/2 hours studying over the weekend. She spent 1 1/4 hours studying on Friday evening and 2 2/3 hours

nata0808 [166]

Answer: $2\ \dfrac{7}{12}\ \text{hours}$

Step-by-step explanation:

Given

Azmyne decided to study a total of $6\ \frac{1}{2}\ hours$

She spent $1\ \frac{1}{4}\ hours$ on Friday and $2\ \frac{2}{3}\ hours$ on Saturday

Hours spent on Friday

$\Rightarrow 1\ \frac{1}{4}=\frac{5}{4}\ hours$

Hours spent on Saturday

$\Rightarrow 2\ \frac{2}{3}=\frac{8}{3}\ hours$

She must study for

$\Rightarrow \dfrac{13}{2}-\dfrac{5}{4}-\dfrac{8}{3}\\\\\Rightarrow \dfrac{13\times6-5\times3-8\times4}{12}=\dfrac{78-15-32}{12}\\\\\Rightarrow \dfrac{31}{12}=2\ \frac{7}{12}\ \text{hours}$