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dmitriy555 [2]
2 years ago
5

Please help asap asap asap

Mathematics
2 answers:
Andrej [43]2 years ago
7 0

Answer:14

Step-by-step explanation:

malfutka [58]2 years ago
4 0

3 \times (4 + 6) - 16 =

3 \times (10) - 16 =

3 \times 10 - 16 =

(3 \times 10) - 16 =

30 - 16 =

14

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Please help ASAP 50 points :(((
Katyanochek1 [597]

Answer:

(f o g) (x) = 36x² + 3

(g o f) (x)  = 6x² + 18

Step-by-step explanation:

f(x) is x² + 3  

g(x) is 6x

(f o g) (x) means for all xs in f replace it with g(x) or 6x

(f o g) (x) = (6x)² + 3  - see 6x is in place of x and 6x is g(x)

(f o g) (x) = 36x² + 3

(g o f) (x)  = 6(x² + 3)  

(g o f) (x)  = 6x² + 18

8 0
3 years ago
Read 2 more answers
What are the x and y-intercepts of the line described by the equation?
KiRa [710]

Answer:

x-int (6.2, 0)

y-int (0, 3.1)

Step-by-step explanation:

x-intercept is found when y = 0.

y-intercept is found when x = 0.

Step 1: Define equation

2x + 4y = 12.4

Step 2: Find x-intercept

<em>Substitute y for 0.</em>

2x + 4(0) = 12.4

2x = 12.4

x = 6.2

(6.2, 0)

Step 3: Find y-intercept

<em>Substitute x for 0.</em>

2(0) + 4y = 12.4

4y = 12.4

y = 3.1

(0, 3.1)

6 0
3 years ago
How do I solve this triangle?
svetlana [45]

Answer:

check the length and the angles and check the height of it

7 0
2 years ago
Hey what's the answer ?<br><br><img src="https://tex.z-dn.net/?f=%28x%20-%20y%29" id="TexFormula1" title="(x - y)" alt="(x - y)"
Varvara68 [4.7K]

Answer:

<em> </em><em>-</em><em>1</em>

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> x</em><em> </em><em>=</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>The </em><em>value</em><em> of</em><em> </em><em>y </em><em>=</em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>we </em><em>need</em><em> to</em><em> find</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>y)</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>put </em><em>the </em><em>value </em><em>of </em><em>above</em><em> </em><em>variables</em><em> </em><em>in </em><em>it</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>hence</em><em>,</em><em> </em><em>(</em><em>1</em><em> </em><em>-</em><em> </em><em>2</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>is </em><em>correct</em><em> answer</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
What term is used to describe the graphical representation of the change in microbial population over time?
ruslelena [56]

Answer:

The term exponential is often used.

Step-by-step explanation:

The term exponential is used to represent changes in population over time.  The idea of (positive) exponential is that the higher the number, the higher the growth. You can relate this with a population, because the higher the population, the more opportunities for it to multiply, thus, the higher it grows.

Usually the way to meassure the population of an species after certain number of years x, you use an exponential function of the form

f(x) = K_0 * a^x

For certain constants K₀ and a. K₀ is the initial population at the start of the experiment and <em>a </em>number of exponential growth. Essentially, the population of the species is multiplied by a during each year.

For example, if K₀ = 1000 and a = 2, then the population at the start of the experiment is 1000. After the first year is 1000*2 = 2000 and after the second year it is 2000*2 = 4000. Note that, not only the population grow during the years, but also the amount that the population increases also grow: in the first year it grows 1000, and between the first and second year it grows 2000.

7 0
3 years ago
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