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mezya [45]
3 years ago
10

The work of a student to solve the equation 3(3x − 4) = 8 + 2x + 5 is shown below: Step 1. 3(3x − 4) = 8 + 2x + 5 Step 2. 6x − 7

= 13 + 2x Step 3. 6x − 2x = 13 + 7 Step 4. 4x = 20 Step 5. x = 5 In which step did the student first make an error and what is the correct step? Step 2, 9x − 12 = 13 + 2x Step 2, 9x − 4 = 2(6 + x + 3) Step 3, 6x + 2x = 13 + 7 Step 3, 6x − 2x = 13 − 7
Mathematics
2 answers:
Nutka1998 [239]3 years ago
5 0
Welll 12 is the power of 12 so the sum of 32 is 12
Sauron [17]3 years ago
4 0
Student made an error in step 2. Correct step is 9x - 12 = 13 + 2x.
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Step-by-step explanation:

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6 0
3 years ago
a circle is centered at the point -3,2) and passes through the point (1,5). The radius of the circle is blank units. The point (
lianna [129]
It's important that you share the complete question.  What is your goal here?  Double check to ensure that you have copied the entire problem correctly.

The general equation of a circle is x^2 + y^2 = r^2.  Here we know that the circle passes thru two points:  (-3,2) and (1,5).  Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.


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Let's check this.  Assuming that the equation of this specific circle is 
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Check the original problem.  If it's different from that which you have shared, share the correct version and come back here for further help.



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