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BigorU [14]
2 years ago
5

The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013. What was the cost of hiring a car for

2 days in 2013?
Mathematics
1 answer:
Goshia [24]2 years ago
7 0

The cost of hiring a car for 2 days in 2013 is Rs. 316.8

<h3>How to find the cost of hiring in 2013 ?</h3>

The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013.

Therefore,

cost of hiring for 2018 = Rs. 264

Therefore,

let

cost of hiring in 2013 = 20%(264) + 264

cost of hiring in 2013 = 20 / 100 × 264 + 264

cost of hiring in 2013 = 1 / 5 × 264 + 264

cost of hiring in 2013 = 264 / 5 + 264

cost of hiring in 2013 = 52.8 + 264

cost of hiring in 2013 = 316.8

Therefore, the cost of hiring a car for 2 days in 2013 is Rs. 316.8.

learn more on cost here: brainly.com/question/1663590

#SPJ1

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Linda's start up cost for her online jewelery store was $250, as she has to pay an additional $60per month to keep it running. W
Goryan [66]

Total Cost = 250 + 60x is the equation that models the given situation

<em><u>Solution:</u></em>

Given that, Linda's start up cost for her online jewelery store was $250

She has to pay an additional $60 per month to keep it running

To find: Equation that models this situation

From given,

Start up cost = $ 250

Let "x" be the number of months she keeps the store running

Additional pay per month = $ 60

Thus, the total cost Linda spend to keep the store running is given as:

Total Cost = Startup cost + (Additional pay per month)(number of months)

Total\ Cost = 250 + 60x

Thus the equation that models the given situation is found

5 0
3 years ago
Please help me nowwww
Llana [10]

Answer:

1) Brazil - 190,000,000

2) Egypt - 77,000,000

3) Australia - 20,000,000

4) Singapore - 4,400,000

5) Luxembourg - 470,000

3 0
3 years ago
Leah's softball team has $437 to spend on equipment. They want to buy 5 gloves that cost $84 each. Leah needs to know if they ha
WITCHER [35]

Answer:

yes she will have enough, they will have 17 dollars left

Step-by-step explanation:

84 times 5 is 420 so she will have enough

6 0
2 years ago
Investigate the difference between compounding annually and simple interest
Gennadij [26K]

Step-by-step explanation:

Simple interest formula

A = P (1 + rt)

Compound interest formula

A = P(1 + \frac{r}{n})^{nt}

a.

A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125

Simple interest is $125

b

. A = 5000 (1 + \frac{0.025}{1})^{1*1}      \\A=5000(1.025)\\A= 5125

Compound interest is $125

c. the result for both a and b are the same

d.

A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375

the simple interest is $375

e

. A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600

the simple interest is $600

h.

A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

6 0
3 years ago
The General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
DerKrebs [107]

Answer:

Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

Step-by-step explanation:

H0 : σ² = 2.66²

H1 : σ² < 2.66²

X²c = (n - 1)*s² ÷ σ²

sample size, n = 40

Sample standard deviation, s = 1.9

X²c = ((40 - 1) * 1.9²) ÷ 2.66²

X²c = 140.79 ÷ 7.0756

X²c = 19.897

Using a confidence level of 95%

Degree of freedom, df = n - 1 ; df = 40 - 1 = 39

The critical value using the chi distribution table is 25.6954

Comparing the test statistic with the critical value :

19.897 < 25.6954

Test statistic < Critical value ; Reject the Null

Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

8 0
3 years ago
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