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BigorU [14]
2 years ago
5

The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013. What was the cost of hiring a car for

2 days in 2013?
Mathematics
1 answer:
Goshia [24]2 years ago
7 0

The cost of hiring a car for 2 days in 2013 is Rs. 316.8

<h3>How to find the cost of hiring in 2013 ?</h3>

The cost for hiring a car for 2 days in 2018 was Rs. 264 which was 20% more than in 2013.

Therefore,

cost of hiring for 2018 = Rs. 264

Therefore,

let

cost of hiring in 2013 = 20%(264) + 264

cost of hiring in 2013 = 20 / 100 × 264 + 264

cost of hiring in 2013 = 1 / 5 × 264 + 264

cost of hiring in 2013 = 264 / 5 + 264

cost of hiring in 2013 = 52.8 + 264

cost of hiring in 2013 = 316.8

Therefore, the cost of hiring a car for 2 days in 2013 is Rs. 316.8.

learn more on cost here: brainly.com/question/1663590

#SPJ1

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3 years ago
Solve for x.<br> I was sure the answer was 2?<br> Please show me the breakdown. THX
Murljashka [212]

Answer:

x = 8 and y = 10

Step-by-step explanation:

Since the figures are congruent:

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6y + x = 68

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Solving that:

2x - 4 = 12

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Step-by-step explanation:

6 0
3 years ago
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Is it possible or not<br> possible to draw a<br> triangle with sides<br> lengths of 4, 5 and 7?
lorasvet [3.4K]

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Step-by-step explanation:

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8 0
3 years ago
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In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.
fomenos

Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

c^{2} =a^{2} +b^{2} -2abCosC    

c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515

2.) use law of cosines to find L

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}  

plug in for b and c:  \frac{860}{sinB} =\frac{1586.225515}{sin126}

cross multiply: \frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}

sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\

L=26

5 0
3 years ago
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