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andreyandreev [35.5K]
2 years ago
5

The point-slope form of a line is y - y1 = m(x-x1), where m is the slope and (x1,

Mathematics
1 answer:
Vlada [557]2 years ago
4 0

Answer

False

FalseThe correct point slope form passing through points (x1,y1) is (y-y1)=m (x-x1)(y−y1)=m(x−x1) 

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can someone please help? And can you also explain how to do it, because I forgot the steps on how to do it ​
alexdok [17]

Answer:

option 3) EF= -7 FG= -7

Step-by-step explanation

X= 1/2

EF= 2X-8

    = 2 X 1/2 -8

    =1 - 8

EF = -7

FG= 4X -9

     = 4X 1/2

     2 - 9

FG     = -7

7 0
2 years ago
Grant needs 2/3 cup of raisins and 3/4 cup of almonds to make trail mix, which statement can be used to find out if their are mo
mina [271]
To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa. 

3*4 = denominator of both
2*4 = numerator of first fraction
3*3 = numerator of second fraction

Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions. 

Overall, there are 1/12 more almonds than raisins.

5 0
3 years ago
Read 2 more answers
Solve the following equation: x÷3-5=-7
Elodia [21]

Answer:

- 6

Step-by-step explanation:

Step 1:

x ÷ 3 - 5 = - 7   Equation

Step 2:

x ÷ 3 = - 2   Add 5 on both sides

Answer:

x = - 6   Multiply 3 on both sides

Hope This Helps :)

3 0
2 years ago
Which set of numbers could represent the lengths of the sides of a right triangle?
wolverine [178]

.............................

4 0
2 years ago
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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
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