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olga55 [171]
3 years ago
13

What is x^2+8x-5 in vertex form? Please explain.

Mathematics
2 answers:
faust18 [17]3 years ago
5 0
x^2+8x-5=\\
x^2+2\cdot4\cdot x-5=\\
x^2+2\cdot4\cdot x+4^2-4^2-5=\\
(x+4)^2-16-5=\\
(x+4)^2-21

lina2011 [118]3 years ago
5 0
<span>x^2+8x-5=\\ x^2-8x+16-21=\\ (x-4)^2-21</span>
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If f(×)=4×^2+1 and g(x)=×^2-5 find (f-g)(×)​
trasher [3.6K]

Answer:

\large\boxed{(f-g)(x)=3x^2+6}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)\\\\=4x^2+1-x^2+5\qquad\text{combine like terms}\\\\=(4x^2-x^2)+(1+5)=3x^2+6

8 0
3 years ago
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Answer:

-3

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