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vitfil [10]
3 years ago
15

An author has 18 pages to send to a publisher. The author has only small envelopes and can't fit all the pages into a single env

elope. It ends up taking 6 envelopes to hold all the pages. If each envelope has the same number of pages in it, how many pages are there in each envelope? A) 2 pages B) 3 pages C) 4 pages D) 5 pages
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0
I’m not really good with riddles so how do I get out of here
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Anton Louis is a junior partner in an accounting firm. He is single
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Step-by-step explanation:

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Simplify <br> 2x x y x 3
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Which is it
2x times y times 3 = 6xy
or,
2xxyx3= 6x^3y

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Whats 18 over 36 simplified
aleksandr82 [10.1K]
18 over 36 simplified is 1/2
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Read 2 more answers
The graph of y=|x|y=∣x∣y, equals, vertical bar, x, vertical bar is shifted down by 999 units.
frosja888 [35]

Answer:

y =  |x| -9

Step-by-step explanation:

The base function is given as

y =  |x|

This graph opens up and has its vertex at the origin.

When we shift the graph of this function down by 9 units, its vertex is now at (0,-9)

The equation of this new graph is

y =  |x| -9

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3 years ago
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A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
3 years ago
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