What is the value of 2\5 + 3\7?

Mathematics

1 answer:

Karolina [17]3 years ago

4 0

29/35

Hope this helps!

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What is the range of function y=√(-2cos^2x+3cosx-1)

Ugo [173]

Hello Friend,here is the solution for your question

so the given function is 
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here in this equation is this quantity :-
(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation 
i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa 

And we know that cosx-3/4 will be minimum if cosx=3/4
therefore put this in (1) we get 
(cosx=3/4)²=0 [ cosx=3/4]
hence the minimum value of the quantity (cosx=3/4)² is 0 

put this in equation (1) 
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
 =√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
 =√1/8
 =1/(2√2)

this is the maximum value now to find the minimum value 

since this is function of root so the value of y will always be ≥0 

hence the minimum value of the function y is 0 

Therefore, the range of function y is [0,1/(2√2)]

__Well,I have explained explained each and every step,do tell me if you don't understand any step._

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3 years ago

What is the range of the data in this stem-and-leaf plot?

sergij07 [2.7K]

The range is the difference between the lowest and the highest number.

the answer is 30.5

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4 years ago

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What is the length of the hypotenuse? 55 ft and 48 ft

34kurt

Answer:

$\sqrt{55^2+ 48^2} = 73$