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1 year ago

Balance the following nuclear reactions

Chemistry

1 answer:

icang [17]1 year ago

6 0

Answer:

1.) ⁴₂He

2.) ⁶₂He

3.) ²⁴²₉₄Pu

4.) ¹₀n

Explanation:

The superscript represents the mass number, which is the total amount of protons and neutrons in an element.

The subscript represents the atomic number, which is the total amount of protons in an element.

You can identify the element based on the atomic number. For instance, all atoms with a subscript/atomic number of 2 must always be helium (He). An element with an atomic number of 0 is represented by the symbol "n". The mass number and atomic numbers must be equal on both sides of the reaction.

1.) ¹₁H + ³₁H → ⁴₂He

-----> Mass Number: 1 + 3 = 4

-----> Atomic Number: 1 + 1 = 2

2.) ⁹₄Be + ¹₁H → He + ⁶₂He

-----> Standard helium (He) has a mass number of 4 and an atomic number of 2

-----> Mass Number: 9 + 1 - 4 = 6

-----> Atomic Number: 4 + 1 - 2 = 2

3.) ²³⁹₉₂U + ⁴₂He → ²⁴²₉₄Pu + ¹₀n

-----> Mass Number: 239 + 4 - 1 = 242

-----> Atomic Number: 92 + 2 - 0 = 94

4.) ²⁷₁₃Al + ¹₀n → ²⁴₁₁Na + ⁴₂He

-----> Mass Number: 24 + 4 - 27 = 1

-----> Atomic Number: 11 + 2 - 13 = 0

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3 years ago

A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container i

Dennis_Churaev [7]

Answer:

1.33 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

Knowing that:

V₁ = 4.0 L, P₁ = 2.0 atm,

V₂ = ??? L, P₂ = 6.0 atm.

Applying in the above equation

(P ₁V₁) = (P₂V₂)

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3 years ago

What is the volume of 40g of sugar given it’s listed density

lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

Rearrange the Equation (1)

d x v = m

v = m/ d ................................................ (2)

put the given values in Equation (2)

v = 40g / 1.59 g/cm³

v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

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3 years ago

A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper

Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

$2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}$

Equation for reaction quotient is as follows.

Q = $\frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}$

= $\frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}$

= 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of $SO_{3}$ as equilibrium is achieved by using Q, is as follows.

This means that there are too much products.

Equilibrium will shift to the left towards reactants.

More $SO_{3}$ is formed.

Partial pressure of $SO_{3}$ increases.

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3 years ago

Please help: A 0.200 M NaOH solution was used to titrate a 18.25 mL HF

algol [13]

The molar concentration of the original HF solution : 0.342 M

Further explanation

Given

31.2 ml of 0.200 M NaOH

18.2 ml of HF

Required

The molar concentration of HF

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)

Titrant = NaOH(1)

Titrate = HF(2)

Input the value :

$\tt 0.2\times 31.2\times 1=M_2\times 18.25\times 1\\\\M_2=0.342$

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2 years ago