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yulyashka [42]
3 years ago
14

For a laboratory investigation some students put a strip of shiny metal into a beaker of blue solution and then stored the beake

r on a shelf
overnight. The next morning, the students recorded observations about the metal and the solution in the box below.
Students' Observations
Exhibit
. The solution is lighter in color,
The volume of solution is the same.
• The metal strip is shiny above the surface of the solution
• The metal strip is not shiny below the surface of the solution.
• The metal strip below the surface of the solution has a dark
coat of flaky material
• When the metal strip is touched, the flaky material falls off.
Based on their observations, can the students correctly conclude that a chemical reaction occurred?
A. No, because the metal strip was still visible
B. Yes, because a new material of a different color formed on part of the metal strip
c. No, because the solution stayed blue
ble solution stayed the same
12 AM

Chemistry
1 answer:
KatRina [158]3 years ago
8 0

Answer:

b

Explanation:

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Consider the following reaction: 2Mg(s)+O2(g)--&gt;2MgO(s) delta H=-1204kJ
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a. The reaction is exothermic.

b. -87,9 kJ

c. 9,60g of Mg(s)

d. 602kJ are absorbed

Explanation:

Based on the reaction:

2Mg(s) + O₂(g) → 2MgO(s) ΔH = -1204kJ

a. The reaction is exothermic. Because ΔH<0. That means the reaction produces heat when occurs

b. 3,55g of Mg(s) are:

3,55g Mg × ( 1mol / 24,305g) = 0,146 moles of Mg(s)

As 2 moles of Mg(s) produce -1204 kJ of heat:

0,146 moles of Mg(s) × ( -1204kJ / 2mol Mg) =  <em>-87,9 kJ</em>

c. If -238 kJ of heat were transferred. The moles of Mg(s) that react must be:

-238kJ × ( 2mol Mg / -1204kJ) = 0,395 moles of Mg(s). In grams:

0,395 moles × ( 24,305g / 1mol Mg) = <em>9,60g of Mg(s)</em>

d. The reverse reaction is:

2MgO(s) → 2Mg(s) + O₂(g)  ΔH = +1204kJ

40,5g of MgO(s) are:

40,5g MgO × ( 1mol MgO / 40,3044g) = 1,00 moles of MgO(s)

As 2 moles of MgO absorbe 1204kJ of energy:

1,00 moles of MgO(s) × ( +1204 kJ / 2mol MgO) = <em>602kJ are absorbed</em>

<em></em>

I hope it helps!

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