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Whitepunk [10]
3 years ago
11

Which of the following statements are TRUE of buffer solutions? 1. A buffer solution can be made by mixing equal concentrations

of ​ acetic acid and sodium acetate. 2. A buffer solution can be made by mixing equal concentrations of ​ hydrochloric acid and sodium chloride. 3. A buffer solution resists changes in pH when small quantities of acid ​ or base are added.
Chemistry
1 answer:
Leokris [45]3 years ago
5 0

Answer:

Option 1 and 3 are correct.

Explanation:

Buffer solution is the solution which resists the change in the magnitude of the pH when small additions of either acid or base is added.  Buffer solutions consist of weak acid and its conjugate base usually which are mixed in relatively equal and large quantities.

Hence,

Option 1. is correct because acetic acid is a weak acid and sodium acetate is the conjugate base of it which are mixed in equal concentrations.

Option 2. is incorrect because HCl and NaCl are both strong acid and salt respectively and will not form a buffer.

Option 3. is correct which is the definition of a buffer solution.

Option 1 and 3 are correct.

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How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium
Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

  • HCl: 2 moles
  • Na: 1 mole
  • NaCl: 2 moles
  • H₂: 1 mole

You know the following masses of each element:

  • H: 1 g/mole
  • Cl: 35.45 g/mole
  • Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

  • HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
  • Na: 23 g/mole
  • NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
  • H₂: 2* 1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • Na: 1 mole* 23 g/mole= 23 g
  • NaCl: 2 moles* 58.45 g/mole= 116.9 g
  • H₂: 1 mole* 2 g/mole= 2 g

So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}

mass of H₂= 4.8 g

<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>

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Answer:

V = 80.65L

Explanation:

Volume = ?

Number of moles n = 5 mol

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