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2 years ago

What is the y and x intercept ? y= x=

Mathematics

1 answer:

cluponka [151]2 years ago

4 0

Answer:

x-intercept is (-3,0)

y intercept is (0,-4)

Step-by-step explanation:

See attached worksheet

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Find the area between y=(x-2)ex and the x-axis from x=2 to x=4.

mojhsa [17]

Answer:

$e^4+e^2$

Step-by-step explanation:

It can be found by integral.

First let's find the intersection points.

$(x-2)e^x = 0$

Only intersection point is x = 2.

And it is asked to find the area in the interval (2, 4).

$\int\limits^4_2 (x-2)e^x \,dx=?$

We will use integration by parts.

$x-2=u\\dx=du\\e^xdx=dv\\e^x=v$

$\int\limits^4_2 (x-2)e^x \,dx=uv-\int vdu=(x-2)e^x-\int e^xdx=(x-2)e^x-e^x=\\\\=(x-3)e^x|^4_2=(4-3)e^4-(2-3)e^2=e^4+e^2$

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3 years ago

How to show numbers are related to each other

ira [324]

Human and non-human species possess a mental system of number representations that appear early in the lifespan and that supports approximate number skills, such as numerical estimation or number comparison. With the later acquisition of language and of symbolic numbers, human beings also develop exact number skills that allow using numbers precisely, such as in counting and arithmetic. The current review points out the behavioral data which either support or challenge these contrasting proposals. In an attempt to provide a comprehensive overview of these mixed data, we carefully took into account the heterogeneity of the available studies regarding the kind of tasks, stimuli or ages of assessment. Also, you can show how the numbers are related simply by identifying the tenth place value of each digit.

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3 years ago

0.60 gal to 0.12 gal as a fraction

adell [148]

Answer:

0.60 gal to 0.12 gal can be rewritten as:

$\frac{0.60}{0.12} =\frac{0.6}{0.6(0.2)} =\frac{1}{0.2}$

$\frac{1}{0.2}*1=\frac{1}{0.2}*\frac{10}{10} =\frac{10}{2} =5$

6 0

1 year ago

Solve using the substitution method: 6x + y =15 4x + 3y = 31

Ksivusya [100]

Answer:

the answers to this are x= 1 and y= 9

3 0

2 years ago

Differentiate the function with respect to x f(x)= x^4/ x^2- 4 Show work

jeyben [28]

Answer:

Step-by-step explanation:

$f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}$

7 0

2 years ago