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Delvig [45]
2 years ago
15

A garden is designed in the shape of a rhombus formed

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

120ft.

Step-by-step explanation:

A garden is designed in the shape of a rhombus formed from 4 identical 30°-60°-90° triangles. The shorter distance across the middle of the garden measures 30 feet. What is the distance around the perimeter of the garden? 120ft.

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Let f(x) = 8x^3 − 22x^2 − 4 and g(x) = 4x − 3. Find f(x) over g(x).
Alenkasestr [34]
You would use the long division technique..

Here it looks like:
<span>
            --------------------
4x − 3 |</span> <span>8x^3 − 22x^2 − 4
---------
           |</span>
           |
<span>           |

and like that,,,

after you do this, you will get

2x^2-4x-3-\frac{13}{4x-3}


hope that helps
</span>
5 0
3 years ago
Tom drove 408 miles using 16 gallons of gas. at this rate, how many miles would he drive using 11 gallons of gas?
Rudik [331]
(11x408) / 16 = 280.5 miles on 11 gal of gas
8 0
3 years ago
QUICK
timama [110]

Answer:$590

Step-by-step explanation:

500*6%=30

30*3=90

500+90=590

8 0
3 years ago
75. Simplify the expression: -2x(4x^2 - 5x + 3)
Karolina [17]

-2x(4x² - 5x + 3)    Distribute/multiply -2x into (4x² - 5x + 3)

(4x²)(-2x) - (5x)(-2x) + (3)(-2x)

-8x³ + 10x² - 6x


Your answer is the 3rd option

3 0
3 years ago
(1) Cos AcosecA=cot A​
Mashutka [201]

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

l.sh =  \cot(A)  \: (proven)

7 0
3 years ago
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