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liq [111]
3 years ago
11

The area of w is 289m². Find the circumference of w

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0
I think 289 x 3.14 which is 907.46 m2

So the answer should be = 907.46 meter square

Hope its help
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Range of 2.45 3.50 2.89 2.99
REY [17]

Answer:

\huge\boxed{\mathrm{Range = 1.05}}

Step-by-step explanation:

<u>Given Data:</u>

2.45 , 3.50 , 2.89 , 2.99

<u>Arrange it in ascending order.</u>

2.45 , 2.89 , 2.99 , 3.50

Range = Highest No - Lowest No.

Range = 3.50 - 2.45

Range = 1.05

6 0
3 years ago
Read 2 more answers
select all the sets that are the three side lengths of right triangles A.8,7,15 B.4, 10, √84 C. √8, 11, √129 D. √1, 2, √3
Semenov [28]

Answer:

<h3>B.4, 10, √84 </h3><h3>C. √8, 11, √129 </h3><h3>D. √1, 2, √3</h3>

Step-by-step explanation:

For any set of three side length of a triangle to be a right angled triangle, the sum of the square of the two of the sides must be equal to the square of the longest side according to pythagoras theorem.

The longest side is always the hypotenuse

For option D, 2 will be the longest side. Since 2 is the hypotenuse, the sum of the square of other two values must be equivalent to the square of 2,

= (\sqrt{1})^{2} +  (\sqrt{3})^{2} \\ = 1=3\\= 4\\= 2^{2} (hypotenuse)

This shows that √1, 2, √3 are three sides of a right triangles.

Similarly for option C, the hypotenuse is √129 being the largest.

To show the sides are that of a right triangles;

= (\sqrt{8}) ^{2} + 11^{2} \\= 8 + 121\\= 129\\= (\sqrt{129})^{2} \\

Since the resulting  value is the square of the hyp, then √8, 11, √129 are three sides of a right triangles.

For option B; 10 is the hypotenuse being the longest sides, To show the sides are that of a right triangles;

=4^{2}+(\sqrt{84})^{2} \\ = 16+84\\= 100\\= 10^{2}

Since the resulting  value is the square of the hyp, then 4, 10, √84  are three sides of a right triangles.

Only option A is wrong since 15² is not equal to the sum of 8² and 7².

4 0
3 years ago
Decide whether it would be more convenient to solve the system of equations by substitution or elimination.
mixer [17]

Answer:

I would use elimination in this scenario. Because in both equations there is a coefficient on both variables, it would be difficult to isolate one variable and would leave the equation as a fraction. Instead, use elimination. Multiply the first equation by -15, which changes it to 10x + 225y = -90, and then subtract the second equation, thus cancelling out the 10x's and letting you solve for Y. Hope this helps!

4 0
2 years ago
HELP HELP HELP HELP
Genrish500 [490]

Answer: -7

Step-by-step explanation: .........................

3 0
3 years ago
I need help please help
Ksenya-84 [330]
- 9 + 12 = 3 or +3

Hopes this helps! =)
3 0
3 years ago
Read 2 more answers
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