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liq [111]
3 years ago
11

The area of w is 289m². Find the circumference of w

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0
I think 289 x 3.14 which is 907.46 m2

So the answer should be = 907.46 meter square

Hope its help
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I need help with a math question
Julli [10]

Answer:

Question 1: 4.5(10^−7)(2(10^4))

=

9/1000

(Decimal: 0.009)

Question 2:

mass of neutron/mass of electron = 2*10-24/(9*10-28)

2x10^(-24)/9x10^(-28)

d is closest.

Question 3:

4(10^3)(12(10^5))

=4000*1200000

=4*1000*12*100000

=(4*12)*(1000*100000)

=48*100000000

=4800000000

And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em><em>if</em><em> </em><em>so</em><em> </em><em>pls</em><em> </em><em>mark</em><em> </em><em>brainliest</em><em> </em><em>and</em><em> </em><em>heart</em><em>/</em><em>rate</em><em>!</em>

3 0
3 years ago
A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit
aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

2x+9y=101

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0
3 years ago
True or False To find the circumference of a circle you multiply the diameter by pi
zavuch27 [327]

Answer:

false

Step-by-step explanation:

Formula: c=2\pir

Circumference= two times pi times radius

4 0
2 years ago
What is the prime factorization of 616?
Leni [432]
A would be the correct answer:)

Hope this helps!
3 0
3 years ago
Read 2 more answers
Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data
EastWind [94]

Solution :

The null and alternative hypothesis is given by

$H_0: \mu = 11$

$H_a: \mu \ne 11$

Assume that the level of significance, α = 0.05

The t-test statistics is, t = 1.484

Degree of freedom :

df = n - 1

   = 14 - 1

   = 13

The P-value is given by

P-value = 2P (T>|t|)

            = 2P(T>|1.484|)

            = 2P(T>1.484)

            = 2(=T.DIST.RT(1.484,13))

            = 0.05

5 0
3 years ago
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