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jarptica [38.1K]
1 year ago
13

Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. the mirror is 2 feet wide and

3 feet long. which quadratic equation can be used to determine the thickness of the frame, x? square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. arrow on the bottom frame with an x and an arrow on the right frame with an x. x2 14x − 2 = 0 2x2 10x − 7 = 0 3x2 12x − 7 = 0 4x2 10x − 1 = 0
Mathematics
1 answer:
Helen [10]1 year ago
6 0

The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.

The correct option is D.

<h3>What is a quadratic equation ?</h3>

A quadratic equation is an algebraic equation of the second degree in x.. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

<h3>According to the given information:</h3>

Total area  = 7 square feet

and,

Total area = Length x Width

So,

7 = (2x + 3)(2x + 2)

7 = 4x2 + 4x + 6x + 6

7 = 4x2 + 10x + 6

4x2 + 10x + 6 - 7 = 0

4x2 + 10x - 1 = 0

Hence,

The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.

To know more about quadratic equation visit:

brainly.com/question/1863222

#SPJ4

I understand that the question you are looking for is:

Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and 3 feet long.  Square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. Arrow on the bottom frame with an x and an arrow on the right frame with an x. Which quadratic equation can be used to determine the thickness of the frame, x?

A. x² + 14x - 2 = 0

B. 2x² + 10x - 7 = 0

C. 3x² + 12x - 7 = 0

D. 4x² + 10x - 1 = 0

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What are the steps for solving this equation, quick please, im in a zoom! -2(-2k+3)+4k=-2(6-3k)+2k
Katyanochek1 [597]

Answer:

0 = -6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2(−2k+3)+4k=−2(6−3k)+2k

(−2)(−2k)+(−2)(3)+4k=(−2)(6)+(−2)(−3k)+2k(Distribute)

4k+−6+4k=−12+6k+2k

(4k+4k)+(−6)=(6k+2k)+(−12)(Combine Like Terms)

8k+−6=8k+−12

8k−6=8k−12

Step 2: Subtract 8k from both sides.

8k−6−8k=8k−12−8k

−6=−12

Step 3: Add 6 to both sides.

−6+6=−12+6

0=−6

8 0
3 years ago
2 2/3 x 2 2/3 please
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2 years ago
Zoe and Hannah share tips in the ratio 3:7. Last week, Zoe received £24. How much did Hannah receive last week?
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Answer:

hannah gets £56

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z   : h

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24 : ?

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8 0
3 years ago
Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S
Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = \sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}

AC = \sqrt{(2-4)^2+(1-1)^2} =2

BC = \sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}

For triangle SRT we have

RS = \sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}

RT = \sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2

ST = \sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}

Therefore their dimensions are equal

However the side with length 2  occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0
3 years ago
Read 2 more answers
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