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vova2212 [387]
2 years ago
7

5th grade . pls help.

Mathematics
1 answer:
fiasKO [112]2 years ago
8 0
4/16 and 1/4 happy to help :)
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What are the vertex, axis of symmetry, maximum or minimum value, and range of y = 3x^2 + 6x − 1?
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The vertex is when x=-b/2a, which is also the line of symmetry. 
in this case, b=6, a=3, so x=-6/6=-1
when x=-1. y=3-6-1=-4

another way to do it is to write the equation into vertex form by making a square:
3x²+6x-1
3(x²+2x-1/3)
3(x²+2x+1-1-1/3))
3(x²+2x+1-4/3))
notice the bold part makes a square:
3(x+1)²-4

Either way, 
the vertex is (-1, -4)
the axis of symmetry is x=-1
the coefficient of x² is 3, a positive number, so this parabola opens upward. the function has a minimum value of y=-4
the range is all real number larger than -4
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