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vova2212 [387]
3 years ago
7

5th grade . pls help.

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0
4/16 and 1/4 happy to help :)
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Alexander is riding his bicycle to school. After one mile, he is a third of the way there. How much farther does he have to ride
Alekssandra [29.7K]
Alexander has to miles to go because if one mile is a third you can simply maltiply by three, then subtract the mile he already went. you maltiply by three because it was a third of the way there
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3 years ago
Which could a translation result in? Select all that apply. a figure getting smaller a figure moving up a figure flipping upside
makkiz [27]

Answer:

A figure moving up, a figure moving left, and a figure moving down.

Step-by-step explanation:

Translations are just moving things around in any direction.

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3 years ago
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Help plssss. picture attached
enot [183]

Answer:30 feet.

Step-by-step explanation: 2 doubled is four and in the bigger triangle it says 5. Therefore 12 doubled and a bit more is 30

3 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
Please help <br> I’ll mark you as a brainliest
masha68 [24]

Answer:

divide 150 by 32 to get 4

Step-by-step explanation:

i used a calculator sorry if wrong im new

8 0
3 years ago
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