Answer:
9x+6
Step-by-step explanation:
2(x-4)= 2x-8
7(x+2)= 7x+14
2x-8+7x+14
clt
9x6
First, you need to use the points to come up with a m (slope). To do this you must use the equation m= y2-y1/x2-x1. label the x in one pair of coordinates x1 and the y, y1. Then label the other x in the other pair of coordinates x2 and the y, y2. use the equation and figure the slope. Next, put the easiest coordinates into point-slope form. The equation you are to use is... y-y1=m(x-x1). Input the values and then distribute the m inside the parenthesis. Then you should be able to do the rest. The final product should be in slope-intercept form.
Convert 3/4 to a denominator of 8 by multiplying by two, getting you:
6/8 + 1/8
Add those and you get D) 7/8
If you would like to solve the system of equations, you can do this using the following steps:
4x^2 + 9y^2 = 72
2x - y = 4 ... 2x - 4 = y
_________
<span>4x^2 + 9y^2 = 72
</span><span>4x^2 + 9 * (2x - 4)^2 = 72
</span>4x^2 + 9 * (4x^2 - 16x + 16) = 72
4x^2 + 36x^2 - 144x + 144 = 72
40x^2 - 144x + 144 - 72 = 0
40x^2 - 144x + 72 = 0
10x^2 - 36x + 18 = 0
5x^2 - 18x + 9 = 0
(5x - 3) * (x - 3) = 0
1. 5x - 3 = 0 ... 5x = 3 ... x = 3/5
2. x = 3
<span>1. y = 2x - 4 = 2 * 3/5 - 4 = 6/5 - 20/5 = -14/5
2. y = 2x - 4 = 2 * 3 - 4 = 6 - 4 = 2
1. (x, y) = (3/5, -14/5)
2. (x, y) = (3, 2)
The correct result would be </span>(3/5, -14/5) and <span>(3, 2).</span>
1. Which polygon or polygons are regular?
A regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).
Therefore your answer is:
A. equilateral triangle
C. square
2. Which polygon is always irregular?
traingle - NOT (equilateral triangle)
trapezoid - YES
square - NOT
hexagon - NOT (regular hexagon)
