Converter will show you the formula and units(:
X= number of hours would it take Jason to wash the van by himself.
2x=number of hours would it take Wendy to wash the van by herserlf.
<span>we calcaulate the fraction of work by Jason during one hour </span>
x hours-----------------------------1 work
1 hour---------------------- fraction of work during one hour.
fraction of work during one hour=(1 hour * 1work) / x hours=1/x
we calculate the fraction of work by Wendy during one hour.
2x hours-----------------------------1 work
1 hour---------------------- fraction of work during one hour.
fraction of work during one hour=(1 hour * 1work) / 2x hours=1/2x
We can suggest this equation:
2 hours(fraction of work by Jason during one hour + fraction of work by Wendy during one hour)=1 work
2(1/x + 1/2x)=1
least common multiple=2x
2(2+1)=2x
2(3)=2x
6=2x
x=6/2
x=3
answer: 3 hours would ti take Jason to wash the van by himself.
do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
