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Karolina [17]
2 years ago
15

What is the additive inverse of the number represented by A​

Mathematics
1 answer:
puteri [66]2 years ago
4 0

Answer:

-A

Step-by-step explanation:

<h2><em><u>h</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u>s</u></em><em><u> </u></em></h2>

<em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u> </u></em><em><u>m</u></em><em><u>e</u></em><em><u> </u></em><em><u>a</u></em><em><u>s</u></em><em><u> </u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u> </u></em><em><u>p</u></em><em><u>l</u></em><em><u>s</u></em>

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igor_vitrenko [27]

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C. Robert can read of a page every minute.

Step-by-step explanation:

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3 years ago
Mr. Hendricks is plotting equivalent ratios on a coordinate plane. One of the ordered pairs is (3,5) Which other ordered pair co
madam [21]

Answer:

(6, 10)

Step-by-step explanation:

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4 0
3 years ago
A man invests a total of $9,493in two savings accounts. One account yields 9% simple interest and the other 10% simple interest.
Tju [1.3M]

$ 1850 was invested in 9% account

<u>Solution:</u>

Given that  

Total amount invested by man in two saving accounts = $9493

Simple interest on one account =9%

Simple interest on second account = 10%

Total interest earned = $930.80

Need to determine amount invested in 9 % account.

Let assume amount invested in account where Simple Interest is 9% = x

And assume amount invested in account where Simple Interest is 10% = y

As total amount invested in two accounts is $9493

=> x + y = 9493      

=> y = 9493 - x                              ------(1)

\text { Simple Interest }=\frac{\text { Amount Invested } \times \text {rate of interest } \times \text {time}}{100}

\begin{array}{l}{\text { Simple interest when rate of interest is } 9 \%=\frac{x \times 9 \times 1}{100}=\frac{9 x}{100}} \\\\ {\text { Simple interest when rate of interest is } 10 \%=\frac{y \times 10 \times 1}{100}=\frac{10 y}{100}}\end{array}

As total interest earned = $930.80

\begin{array}{l}{\Rightarrow \frac{9 x}{100}+\frac{10 y}{100}=930.80} \\\\ {\Rightarrow 9 x+10 y=930.80 \times 100} \\\\ {\Rightarrow 9 x+10 y=93080}\end{array}

On substituting value of y from equation(1) in above equation , we get

9x + 10 (9493 – x) = 93080

=> 9x  + 94930 – 10x = 93080

=> -x = 93080 – 94930

=> -x = -1850

=> x = 1850  

Amount invested in account where Simple Interest is 9% = x  = $1850

Hence $1850 was invested in 9% account.

5 0
3 years ago
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iogann1982 [59]
2(c-3)=s

because you have to subtract 3 years from sherman's age first, so you need the parentheses
7 0
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