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Scilla [17]
3 years ago
5

Analyze the following computer password in terms of how secure it might be. Describe the criteria you use in determining its str

engths and weaknesses. born2ski4evr!
Mathematics
2 answers:
Mice21 [21]3 years ago
7 0
For maximum security I would advise you to add capital letters
Mkey [24]3 years ago
6 0

Answer:

The password is less secure.

Step-by-step explanation:

We have the password given by,

born2ski4evr!

It is required to determine the strengths and weaknesses of this password.

From the given password, we can see that,

As the password has more than 8 characters and it includes a special character ' ! ' and numbers 2, 4. Also, the combination of letters and numbers are in jumbled form. These contributes to the strengths of this password.

Moreover, as the password does not contain any 'capital letter', this will make it less secure and hence becomes its weakness.

To convert this password into a strong password, some of the letters should be changed into their capital form such as,

BorN2sKi4evR!

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What is the value of 4y+2y-8 if y=0.5
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Answer:

-5

Step-by-step explanation:

4x0.5=2

2x0.5=1

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Simplify the variable expression by evaluating its numerical part.
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Step-by-step explanation:

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3 years ago
If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
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