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DochEvi [55]
3 years ago
15

A Recipe for party mix calls for 3/4 cup of cereal , 1/4 Cup of walnuts, 5/8 cup of crackers , and 1/2 cup of raisins . determin

e the number of cups in the mix. write the answer in the simplist form ?
A. 2 1/8
B. 1 1/8
C. 10/18
D. 17/8
Mathematics
2 answers:
yuradex [85]3 years ago
4 0
3/4=6/8, 1/4=2/8, 5/8=5/8, 1/2=4/8.
6/8 + 2/8 + 5/8 + 4/8 = 17/8
17/8 = 2 1/8
The answer is A: 2 1/8
Semmy [17]3 years ago
3 0
Have to find the same denominator. 16. 3/4= 12/16 ; 1/4=4/16 ; 5/8 10/16 ; 1/2 = 8/16  34/16 

which is 2 1/8
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avanturin [10]

Answer:

a 10.21

Step-by-step explanation:

because 20 - 9.79 = 10.21

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3 years ago
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Johnny's town is having an old-fashioned circus under a large tent. In order to keep the tent from falling down, workers must ti
Zepler [3.9K]

Answer: 62 feet approximately.

Step-by-step explanation:

1. Based on the information given in the problem, you can draw a right triangle as the one shown in the image attached, where the height of the tent is represented with x. Therefore, you can calculate it as following:

sin\alpha=\frac{oppostite}{hypotenuse}

Where:

\alpha=62\°\\opposite=x\\hypotenuse=70

2. Substitute values and solve for x, then the height of the circus tent is:

sin(62\°)=\frac{x}{70}\\x=70*sin(62\°)

x=61.81≈62ft

7 0
3 years ago
The table below represents which equation? x -1,0,1,2 y -10,-6,-2,2
goblinko [34]
(-1,-10)(0,-6)
slope = (-6 - (-10) / (0 - (-1) = 4/1 = 4

y = mx + b
slope(m) = 4
(0,-6)...x = 0 and y = -6
sub and find b, the y int
-6 = 4(0) + b
-6 = b

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8 0
3 years ago
30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now
barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0
1 year ago
Answer this Q QUIQLY PLZ
MariettaO [177]

Answer: 3. HAVE AN AMAZING DAY

8 0
3 years ago
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