Question

A binomial probability experiment is conducted with the given parameters. compute the probability of x successes in the n independent trials of the experiment. n=9, p=0. 3,

Answer 1

If the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.

Given that the value of n is 9 and the value of p is 0.3.

We are required to find the probability when the value of x is equal to 3.

Probability is the calculation of chance of happening an event among all the events possible.It lies between 0 and 1.

Probability=Number of items/total items.

Binomial probability is basically the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes.

$(a+b)^{n}$=$nC_{0}a^{0} b^{n-0} +nC_{1}a^{1} b^{n-1} +................nC_{n}a^{n} b^{0}$

We have to find the value when n=9, p is 0.3 and r=3.

=$9C_{3} (0.3)^{3} (1-0.3)^{6}$

=9!/3!6!*0.027*0.16807

=84*0.00453789

=0.381182

Hence if the probability of obtaining success is 0.3 and the value of n is 9 then the probability at the value of x be 3 is 0.3811.

Learn more about probability at brainly.com/question/24756209

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