All categories

3 years ago

What is the solution to 5 + 6x = 2x - 7

Mathematics

2 answers:

Olenka [21]3 years ago

6 0

The answer is x= - 3 :)

Doss [256]3 years ago

4 0

Step-by-step explanation:

5+6x=2x-7

We simplify the equation to the form, which is simple to understand

5+6x=2x-7

We move all terms containing x to the left and all other terms to the right.

+6x-2x=-7-5

We simplify left and right side of the equation.

+4x=-12

We divide both sides of the equation by 4 to get x.

x=-3

You might be interested in

Find the sum : 1/2( x+7) = 32

Gennadij [26K]

Answer:

x=52

I think it is the answer

4 0

3 years ago

Read 2 more answers

Solve the inequality<br> 3 + 9x >4(x+7)<br> pls help

alexandr402 [8]

Answer:

x<5

Step-by-step explanation:

the greater sign will firstly be changed to = for better solving so we obtain

3+9x=4(x+7)by opening bracket

3+9x=4x+28

9x-4x=28-3

5x=25

divide all through by 5x

we obtain

x=5

the greater sign change here

which is x<5

8 0

2 years ago

Find the area of the area of the following figure please answer I’ll make Brainly

serg [7]

Answer: 91

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Hello! Anyone able to help me with question 3 + explanation too? Thanks!

taurus [48]

Answer:

2 or 12

Step-by-step explanation:

The answer that we will use this equation 1/t1 +1/t2=1/ttotal

where t1 is the time of smaller pipe while t2 is the of the larger pipe

Given t total =4 while t2 is equal to t2=t1-6

So know you can solve the problem by changing it into (2t1-6)/(t1*(t1-6))=1/4

8( t1-3)=(t1^2-6t1)

t1^2-14t1+24=0

t1=2 or 12

5 0

3 years ago

Read 2 more answers

f(x) = square root ( x^4 -16x^2) let f be the function given by: . . a) Find the domain of f.. b) Find f '(x). c) Find the slope

Bond [772]

A ) The domain:
$x^{4} -16 x^{2} \geq 0 \\ x^{2} ( x^{2} -16) \geq 0 \\ x^{2} -16 \geq 0 \\ x^{2} \geq 16$
x ≤ -4 and x≥ 4 or: x ∈ ( - ∞ , - 4 ) ∪ ( 4 , + ∞ )
b ) f ` ( x ) = $\frac{1}{2 \sqrt{ x^{4} -16 x^{2} } } *( 4 x^{3} - 32 x ) = \\ = \frac{2x( x^{2} -8)}{ \sqrt{ x^{4}-16 x^{2} } }$
c ) The slope of the line normal to the graph at x = 5
m = -1 / f `(x)
f ` ( x ) = $\frac{10(25-8)}{ \sqrt{625-400} }= \frac{10*17}{15} = \frac{34}{3}$
m = - 3/34

8 0

3 years ago