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Eva8 [605]
1 year ago
15

6x + 4y=10 12x + y= -29

Mathematics
1 answer:
Olin [163]1 year ago
3 0

Answer: x=-3    y=7.

Step-by-step explanation:

\displaystyle\\\left \{ {{6x+4y=10\ \ \ \ \ (1)} \atop {12x+y=-29\ \ \ \ (2)}} \right.\\  We\  multiply\  both\  sides\  of\  equation\  (1)\  by\  -2:\\\left \{ {{(-2)*6x+(-2)*4y=(-2)*10} \atop {12x+y=-29}} \right. \\\\\left \{ {{-12x-8y=-20} \atop {12x+y=-29}} \right. \\We\  summarize\  equations\  (1)\  and\  (2):\\-7y=-49\\-7*y=-7*7\\Divide\  both\  sides\  of\  the\  equation\  by\  -7:\\y=7.\\We\  substitute\  the\  value\  of\  y\  into \ equation\  (1):\\6x+4*7=10\\6x+28=10\\6x+28-28=10-28\\6x=-18\\6*x=6*(-3)\\Divide\  both\  sides\  of\  the\  equation\  by\  6:\\x=-3.

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What is the width of the rectangle shown below? <br>4x + 3 <br>A = 8x2 – 10x – 12
ozzi

Answer:

<h2><em>2x-4</em></h2>

Step-by-step explanation:

Area of a rectangle = Length * Width

Given parameters

Area A = 8x2 – 10x – 12

Length of the rectangle = 4x+3

Required

Width of the rectangle.

Substituting the given parameters into the formula

8x2 – 10x – 12  = (4x+3)*width

width = 8x2 – 10x – 12 /4x+3

S

Factorizing the numerator

8x² – 10x – 12

= 2(4x²-5x-6)

= 2(4x²-8x+3x-6)

= 2(4x(x-2)+3(x-2))

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Width = 2(4x+3)(x-2)/4x+3

Width = 2(x-2)

Width = 2x-4

<em>Hence the width of the rectangle is 2x-4</em>

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